Hey there!
Molar mass of magnesium is 24.305.
One mole of magnesium has a mass of 24.305 grams.
We have 1.75 moles.
Multiply 1.75 by 24.305.
1.75 x 24.305 = 42.5
1.75 moles of magnesium has a mass of 42.5 grams.
Hope this helps!
Answer:
T₂ = 150 K
Explanation:
Given data:
Initial volume of gas = 804 mL
Initial temperature = 27°C (27+273=300 K)
Final temperature = ?
Final volume = 402 mL
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = V₂T₁/V₁
T₂ = 402 mL × 300 K / 804 mL
T₂ = 120,600 mL.K / 804 mL
T₂ = 150 K
Answer:
+2.5
Explanation:
So the oxidation number of S in Na2S4O6is +2.5.
