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3241004551 [841]
3 years ago
9

The methylene chloride solution is filtered through sodium sulfate to:

Chemistry
1 answer:
Vlad [161]3 years ago
5 0

Answer:

C. Dry the methylene chloride by removing water

Explanation:

Anhydrous sodium sulfate is known for its high capacity to absorb water, for this reason it is widely used in laboratories as a drying agent.

Sodium sulfate is a neutral molecule so it cannot be used to neutralize and is very stable, so it is difficult to precipitate organic molecules.

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A galvanic cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). W
Agata [3.3K]

Answer : The 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Explanation :

Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the voltaic cell or electrochemical cell.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

We are taking the value of standard reduction potential form the standard table.

E^0_{[Ag^{+}/Ag]}=+0.80V

E^0_{[Cu^{2+}/Cu]}=+0.34V

In this cell, the component that has lower standard reduction potential gets oxidized and that is added to the anode electrode. The second forms the cathode electrode.

The balanced two-half reactions will be,

Oxidation half reaction (Anode) : Cu(s)\rightarrow Cu^{2+}(aq)+2e^-

Reduction half reaction (Cathode) : Ag^{+}(aq)+e^-\rightarrow Ag(s)

Thus the overall reaction will be,

Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

From this we conclude that, 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Hence, the 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

7 0
3 years ago
is the atomic mass of chlorine represented by the mass of the most common naturally occurring isotope in chlorine?
IrinaVladis [17]
Combine the number of its Protons and Neutrons and you will have its atomic mass.
8 0
3 years ago
A) 30.22 g NaCl x 1 mol NaC l =      58.4430 Molar mass (g) NaCl=0.5171 mol NaCl
jekas [21]
The third question requires you to solve for the weight of sodium (Na) and weight of Chloride (Cl) from the calculated moles of each element Na, and Cl.

So, you need to multiply the calculated moles of Na with its molar mass (23 g/ mol) to get the answer for Na. And multiply the calculated moles of Cl with its molar mass (35.45 g/mol) to get the answer for Cl. 
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If someone is suffering from the problem of acidity after overeating, which of the following would you suggest as remedy ?
kolezko [41]

Answer:

nth

Explanation:

6 0
3 years ago
9.25 * 10^21 pennies if how many moles
Brrunno [24]
According  to  Avogadro constant   1  mole  =  6.02  x   10^23    what  about   9.25  x10  ^21

that  is    1  mole  x   (  9.25  x10  ^21)  /  (6.02 x10^23)  =  0.0154  moles
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3 years ago
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