Answer:
where is the answer options because it sounds like I need some
The volume of a 1.86-carat diamond in cubic centimeters is 0.106 cm³
Given,
The density of a diamond is 3.513 g/cm³.
We have to find out the volume of a 1.86-carat diamond in cubic centimeters.
Convert the units of the diamond from carat to grams, we have:
(1.86 carats) x (0.200 g / 1 carat) = 0.372 g
The volume of the diamond is obtained by dividing the mass by the density, therefore using the formula, we get
v = m / d
v = 0.372 g / (3.51 g/cm³) = 0.1059 cm³
or, v = 0.106 cm³ (approx)
Therefore, the volume of a 1.86-carat diamond is approximately 0.106 cm³.
To learn more about the volume, visit: brainly.com/question/1578538
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Hello, Ginamuhs2!
The oxidizing agent in 2H2S + 3O2 → 2SO2 + 2H2O is the oxygen.
I hope this helps;)
Answer:
ΔS° = -268.13 J/K
Explanation:
Let's consider the following balanced equation.
3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)
We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:
ΔS° = ∑np.Sp° - ∑nr.Sr°
where,
ni are the moles of reactants and products
Si are the standard molar entropies of reactants and products
ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]
ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]
ΔS° = -268.13 J/K
Answer:
Ka = ( [H₃O⁺] . [F⁻] ) / [HF]
Explanation:
HF is a weak acid which in water, keeps this equilibrium
HF (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + F⁻ (aq) Ka
2H₂O (l) ⇄ H₃O⁺ (l) + OH⁻ (aq) Kw
HF is the weak acid
F⁻ is the conjugate stron base
Let's make the expression for K
K = ( [H₃O⁺] . [F⁻] ) / [HF] . [H₂O]
K . [H₂O] = ( [H₃O⁺] . [F⁻] ) / [HF]
K . [H₂O] = Ka
Ka, the acid dissociation constant, includes Kwater.
