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Leto [7]
3 years ago
6

As pressure decreases so does boiling point. One reason astronauts wear space suits in space is because of the decreased pressur

e in space. Explain what might happen to the blood of an astronaut subjected to extremely low pressures.
Chemistry
2 answers:
IgorLugansk [536]3 years ago
8 0
He'll die because his blood pressure is decreasing
PilotLPTM [1.2K]3 years ago
4 0
First, we need to be aware that our blood is also  a form of liquid.
So, when the astronaut is placed in within the environment that has decreased pressure,  the temperature inside the astronaut's body will definitely increase but it won't cause the boiling effect like in water (it won't even break the arteries). But it could endanger the astronaut's life because it makes the blood unable to circulate properly due to unstable blood pressure
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VLD [36.1K]

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3 years ago
3.0 x 10 23 molecules of element Z have a mass of 38 g. What is the mass of 1 mole?
mylen [45]
Does this make sense ?

6 0
3 years ago
2LiClO+KHSO - Li2SO4 + Cl2 + KOOH
agasfer [191]

Answer:

2.5 moles of KOOH are produced.

Explanation:

1)Given data:

Number of moles of KOOH produced = ?

Number of moles of LiClO = 5 mol

Solution:

Chemical equation:

2LiClO +  KHSO₄     →      Li₂SO₄ + Cl₂ + KOOH

now we will compare the moles of KOOH and LiClO.

                 LiClO          :          KOOH

                    2              :              1

                   5               :             1/2×5 = 2.5

2.5 moles of KOOH are produced.

4 0
3 years ago
What usally happens when two continentel plates converge
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5 0
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Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.
Maksim231197 [3]

The theoretical yield of SnS_2 will be 4.20 grams while the percent yield will be 7.93%

<h3>How is yield calculated?</h3>

From the equation of the reaction, the mole ratio of SnBr_4 to Na_2S is 1:2.

Mole of 48.1 mL, 0.478 M  SnBr_4 = 0.478 x 48.1/100 = 0.023 mols

Mole of 48.8 mL, 0.160 M   Na_2S = 0.160 x 48.8/1000 = 0.0078 moles

SnBr_4Na_2S is the limiting reactant.

Mole ratio of  SnBr_4  and SnS_2 = 1:1

Equivalent mole of  SnS_2 = 0.023 moles

Mass of 0.023 noles SnS_2= 0.023 x 182.81 = 4.20 grams

With 0.0333 g of SnS_2 recovered, percent yield = 0.333/4.2 x 100 = 7.93%

More on yields of reactions can be found here: brainly.com/question/17042787

#SPJ1

Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.

SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)

Suppose a student adds 48.1 mL of a 0.478 M solution of SnBr4 to 48.8 mL of a 0.160 M solution of Na2S.

1) Calculate the theoretical yield of SnS2. ;

2) The student recovers 0.333 g of SnS2. Calculate the percent yield of SnS2 that the student obtained.

7 0
2 years ago
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