10N 20N 12N What is the net force?

Define "Monosaccharide", "Disaccharide", "Oligosaccharide", "Polysaccharide", and "Glucoconjugate"

avanturin [10]

Explanation:

Monosaccharides are the elementary form of the sugar and most basic units of the carbohydrates. These sugars cannot be further hydrolyzed to form the simpler chemical compounds. The general formula is $C_nH_{2n}O_n$ . Example: Glucose and fructose.

Disaccharide is sugar which is formed when the two monosaccharides are joined by the glycosidic linkage. Disaccharides are soluble in the water. Examples: sucrose and lactose.

Oligosaccharide is the saccharide polymer which contains small number of the monosaccharides. They can have many functions like the cell recognition and the cell binding. Example: glycolipids which have role in immune response.

Polysaccharides are the polymeric carbohydrate molecules which are composed of the long chains of the monosaccharide units that are bound together by the glycosidic linkages which on the hydrolysis give constituent monosaccharides or th eoligosaccharides. Example: Starch.

Glycoconjugates is general classification for the carbohydrates which are covalently linked with the other chemical species such as peptides, proteins, saccharides and lipids. Example: Blood proteins

6 0

2 years ago

Name:_____________________________________________________ Date:___________ Period:_________ 3/23 - 3/27 Assignment 1: Gas Law P

crimeas [40]

Answer:

The answers are;

1. 8.2 liters

2. 1214.84 ml

3. 318.027 K

4. 4.00 l.

Explanation:

1. Boyle's law states that the volume of given mass of gas is inversely proportional to its pressure at constant temperature

that is

P₁·V₁ = P₂·V₂

Where:

P₁ = Initial pressure = 40.0 mm Hg

V₁ = Initial volume = 12.3 liters

P₂ = Final pressure = 60.0 mm Hg

V₂ = Final volume = Required

From P₁·V₁ = P₂·V₂, V₂ is given by

$V_2=\frac{P_1\cdot V_1}{P_2} = \frac{40.0 mm Hg\cdot 12.3 l}{60.0 mm Hg}$ = 8.2 l

The volume reduces to V₂ = 8.2 liters

2. Here Charles law states that

$\frac{T_1}{V_1} =\frac{T_2}{V_2}$

T₁ = Initial temperature = 27.0 °C = 300.15 K

V₁ = Initial volume = 900.0 mL

T₂ = Final temperature = 132.0 °C = 405.15 K

V₂ = Final volume = Required

Therefore $V_2 =\frac{T_2\cdot V_1}{T_1}$ = $\frac{405.15 K\times 900.0 mL}{300.15 K}$ = 1214.84 ml

V₂ = 1214.84 ml

3. Gay-Lussac's Law states that

$\frac{T_1}{P_1} =\frac{T_2}{P_2}$

Where:

P₁ = Initial pressure = 15.0 atmospheres

T₁ = Initial temperature = 25.0 °C = 298.15 K

P₂ = Final pressure = 16.0 atmospheres

T₂ = Final temperature = Required

∴ $T_2 = \frac{T_1\times P_2}{P_1}$

= $\frac{298.15 K\times 16.0atm}{15.0atm}$ = 318.027 K

T₂ = 318.027 K

4. Avogadro's law states that,

Equal volume of all gases at the same temperature and pressure contain equal number of molecules.

Therefore if 5.00 moles of gas occupies 2.00 l volume, then

1 moles will occupy 2.00/5 l volume and

10 moles will occupy 2.00/5 × 10 or 4.00 l volume.

6 0

3 years ago

PLEASE HELP ME BUT FAST!

Elina [12.6K]

Hey, i add an answer so you can give the other person brainlest :)

7 0

2 years ago

Read 2 more answers

Help plz:))) I’ll mark u Brainliest

loris [4]

Answer:

We report an unusual case of mercury vapor poisoning from using a heated tobacco product. The suspect had added grains of mercury into 20 cigarettes in a pack. When a 36-year-old Japanese man inserted one of these cigarettes into the battery powered holder, it was heated to a temperature of 350 °C, and he inhaled vaporized mercury. After using 14 of the cigarettes over 16 h, he noticed he had flu-like symptoms so he visited the hospital. Although no physical abnormalities were revealed, 99 μg/L of mercury was detected in his serum sample. His general condition improved gradually and his whole blood mercury level had decreased to 38 μg/L 5 days later. When the remaining six cigarettes in the pack were examined, many metallic grains weighing a total of 1.57 g were observed. Energy dispersive X-ray fluorescence spectrometry confirmed the grains as elemental mercury. Accordingly, the victim was diagnosed with mercury poisoning. Because the mercury was incorporated into cigarettes, an unusual and novel intoxication occurred through the heating of the tobacco product. Both medical and forensic scientific examination confirmed this event as attempted murder.

Explanation:

3 0

2 years ago

in an experiment 3.5g of element A reacted with 4.0g of element G to form a compound Calculate the empirical formula for this co

kolezko [41]

Additional information

Relative atomic mass(Ar) : A=7, G=16

The empirical formula : A₂G

<h3>Further explanation</h3>

Given

3.5g of element A

4.0g of element G

Required

the empirical formula for this compound

Solution

The empirical formula is the smallest comparison of atoms of compound forming elements.

The empirical formula also shows the simplest mole ratio of the constituent elements of the compound

mol of element A :

$\tt mol=\dfrac{mass}{Ar}\\\\mol=\dfrac{3.5}{7}=0.5$

mol of element G :

$\tt mol=\dfrac{4}{16}=0.25$

mol ratio A : G = 0.5 : 0.25 = 2 : 1

4 0

2 years ago

10N 20N 12N What is the net force?​

10N 20N 12N What is the net force?