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mihalych1998 [28]
2 years ago
13

The forms a food substance into small balls and then pushes them into the_____.

Chemistry
1 answer:
KatRina [158]2 years ago
5 0
During the digestion process, the first step would be mastication, lubrication with the saliva, and later on is being formed into a bolus. Bolus is the term used for food substance that is turned into small balls. When the bolus is formed, this is then pushed or moved to the stomach.
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1. B
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2. In order to balance the equation, you must sure there are equal moles of each element on the left and right side of the equation:
2C₂H₆ + 7O₂ → 4CO₂ + ₆H₂O

3. The number of moles of sodium atoms on the left of the equation must be equal to the number of moles of sodium atoms on the right, as per the law of conservation of mass. The answer is B.

4. C.
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5. B. 
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2 years ago
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6 0
3 years ago
How many atoms of chlorine (Cl) are shown below? <br><br> 5 CaCl2
Jobisdone [24]
The answer is not C...
5 0
3 years ago
How many litres (L) of oxygen at STP can be obtained from 110 g of potassium chlorate? [R=0.0821 L.atm/K.mol]
lisabon 2012 [21]
Balance the equation first:

2 KClO3 (s) ---> 2 KCl (s) + 3 O2 (g)

Moles of KClO3 =  110 / 122.5 = 0.89

Following the balanced chemical equation:
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= 1.34 moles

So, Volume at STP = nRT / P

T = <span>273.15 K
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So, V = (1.34 x 0.0821 x 273.15) / 1  =  30.2 L</span>
3 0
3 years ago
How many moles of calcium chloride are contained in a 333 gram sample?
Bogdan [553]

Answer & Explanation:

The molar mass of calcium chloride is 110.98 g/mol. We can use this information to solve this problem. We can set up our equation like this..

\frac{333 g(CaCl2)}{} *\frac{1mol(CaCl2)}{110.98g(CaCl2)}

Multiply straight across on the top and straight across on the bottom.

\frac{333}{110.98}

Now divide.

\frac{333}{110.98}=3.00

So, there are 3.00 moles of calcium chloride contained in a 33 gram sample which is answer choice D.

6 0
3 years ago
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