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djyliett [7]
3 years ago
14

You have $25 to buy 6 fishing lures. Write and solve an inequality that represents the prices you can pay per fishing lure.

Mathematics
1 answer:
Rus_ich [418]3 years ago
6 0

We are given that we have $25 to pay for 6 fishing lures.

We can make an equality for this as follows:

Suppose price of one fishing lure is x dollars.

So we will use unitary method to find price of 6 fishing lures.

Price of 6 fishing lures = 6 * ( price of one fishing lure) = 6* x = 6x

Now we only have 25 dollars with us, so the price of 6 fishing lures has to be less than or equal to 25 dollars.

So creating an inequality,

6x\leq25

Now in order to find price for one fishing lure, we have to solve this for x.

Dividing both sides by 6 we have,

x\leq\frac{25}{6}

Converting to decimal,

x\leq4.167

Answer : The price of one fishing lure must be less than or equal to $4.167

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Anaya’s Team won 20 games

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Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes
yaroslaw [1]

Answer:

\frac{y^{2}}{25}-\frac{x^{2}}{3}=1

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: (0,-\sqrt{28}),(0,\sqrt{28})

eje conjugado = 2\sqrt{3}

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

de los focos podemos obtener que:

c=\sqrt{28}

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b=\sqrt{3}

podemos utilizar la siguiente fórmula para obtener a:

c^{2}-a^{2}=b^{2}

si despejamos a en la ecuación obtenemos lo siguiente:

a=\sqrt{c^{2}-b^{2}}

ahora podemos sustituir los valores:

a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}

a=\sqrt{28-3}

a=\sqrt{25}

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1

\frac{y^{2}}{25}+\frac{x^{2}}{3}=1

si graficamos la hipérbola, queda como en el documento adjunto.

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Solve for x<br> 6/7= x+2/8
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Answer:

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Read 2 more answers
What is the value of X?
PIT_PIT [208]

Answer:

The last choice:  x = 3.

Step-by-step explanation:

M < WYX = 1/2 * 78 = 39 degrees ( angle  opposite te arc of 78 degrees).

Therefore m < XWY = 180-114-39 = 27 degrees.

7x + 6 = 27

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3 0
3 years ago
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