In case 1, a force f is pushing perpendicular on an object a distance l/2 from the rotation axis. in case 2 the same force is pu
1 answer:
In case 1, the torque is given by the product between the force and the arm:
In case 2, the torque is given by the product between the component of the force perpendicular to the arm and the arm itself, so we have:
and since
is larger than 1, than the torque in case 2 is larger than the torque in case 1.
In case 2, the torque is given by the product between the component of the force perpendicular to the arm and the arm itself, so we have:
and since
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The magnitude of the magnetic force per unit length on the top wire is
2×10⁻⁵ N/m
<h3>How can we calculate the magnitude of the magnetic force per unit length on the top wire ?</h3>To calculate the magnitude of the magnetic force per unit length on the top wire, we are using the formula
F=
Here we are given,
= magnetic permeability
= 4×10⁻⁷ H m⁻¹
If= 12 A
d= distance from each wire to point.
=0.12m
Now we put the known values in the above equation, we get
F=
Or, F =
Or, F= 2×10⁻⁵ N/m.
From the above calculation, we can conclude that the magnitude of the magnetic force per unit length on the top wire is 2×10⁻⁵ N/m.
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Answer:
Explanation:
For answer this we will use the paralell axis theorem:
I=
Where is the moment of inertia of the center of mass, M is the mass of the sphere and d is the distance between the center of mass and the axis for rotate, then: