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True [87]
3 years ago
10

In case 1, a force f is pushing perpendicular on an object a distance l/2 from the rotation axis. in case 2 the same force is pu

shing at an angle of 30 degrees a distance l from the axis. 1 in which case is the torque due to the force about the rotation axis biggest?
Physics
1 answer:
Serggg [28]3 years ago
6 0
In case 1, the torque is given by the product between the force and the arm:
\tau_1 = F \cdot  \frac{L}{2}

In case 2, the torque is given by the product between the component of the force perpendicular to the arm and the arm itself, so we have:
\tau_2 = F \cos 30^{\circ} L=F  \frac{ \sqrt{3} }{2} L =  \sqrt{3} F  \frac{L}{2}= \sqrt{3} \tau_1

and since \sqrt{3} is larger than 1, than the torque in case 2 is larger than the torque in case 1.
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