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ra1l [238]
3 years ago
7

Can anyone help with thiss??

Chemistry
1 answer:
IrinaVladis [17]3 years ago
5 0
  1. l
  2. kg
  3. cm
  4. gm
  5. ml
  6. km,m
  7. m
  8. nm
  9. mg
  10. ms
  11. gm
  12. nm
  13. .
  14. .
  15. l,gm
  16. .
  17. kg
  18. m
  19. gm,m
  20. s

Hope this helps :-). And....

ml: milliliter

kg: kilogram

m: meter

mg: milligram

mm: millimeter

ms: millisecond

l: liter

km: kilometer

µg: micro gram

cm: centimeter

g: gram

nm: nano meter


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Answer:

eukaryotic

Explanation:

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Statements
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1. Make an observation : My toaster doesn't toast my bread

2. Ask a question : Why doesn't my toaster work?

3. Form a hypothesis : My coffeemaker works when plugged into the outlet

4. Make a prediction : If something is wrong with the outlet, then my coffeemaker also won't work when  plugged into it

5. Conduct an experiment : I plug my coffeemaker into the outlet

6. Analyze the results : There is something wrong with the electrical outlet

Explanation:

The solution to the problem is as shown above.

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  • To investigate this, the forms a hypothesis. A hypothesis is a scientific guess. It is a tentative proposition about an investigation.
  • The researcher then makes a prediction about the outlet that might be faulty.
  • With this background, he goes on to carry out an experiment to substantiate his findings. This is seen when he plugs the coffeemaker into the outlet.
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purpose of experiment brainly.com/question/5096428

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Which reaction below represents a balanced, double replacement chemical reaction? A) C2H5OH + 3O2 → 2CO2 + 3H2O B) Rb2O + Cu(C2H
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Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

Explanation :

First we have to calculate the moles of n-butane.

\text{Moles of n-butane}=\frac{\text{Mass of n-butane}}{\text{Molar mass of n-butane}}

Given:

Molar mass of n-butane = 58.12 g/mole

Mass of n-butane = 58.3 g

Now put all the given values in the above expression, we get:

\text{Moles of n-butane}=\frac{58.3g}{58.12g/mol}=1.00mol

Now we have to calculate the energy required.

Q=\frac{\Delta H}{n}

where,

Q = energy required

\Delta H = enthalpy of fusion of solid n-butane = 4.66 kJ/mol

n = moles = 1.00 mol

Now put all the given values in the above expression, we get:

Q=\frac{4.66kJ/mol}{1.00mol}=4.66kJ

Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

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