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3 years ago

How are the IUPAC molecular naming system and the zoological taxonomic naming system similar and how are they different?

2 answers:

8 0

Well the IUPAC naming system is for naming organic compounds in chemistry whereas the taxonomic hierarchical naming system is for classifying and naming species of organisms and finding relationships in terms of physical characteristics. The only way I'd say that they're similar is in the way they actually name the compound/species. E.g, in chemistry, you always have a base name and to that base name you can add a suffix and/or prefix(es). And in biology, you always have the first bit of the me which is the generic name and the second bit of the name which is the specific name. I know this probably wasn't very helpful but this is a very odd question if it's one that would be in an exam because chemistry and biology wouldn't usually be mixed together...

belka [17]3 years ago

6 0

Answer:

The similarity between the IUPAC naming and the zoological taxonomic nomenclature is that both are used for naming and providing identity.

The difference between the IUPAC naming and the zoological taxonomic nomenclature system is that the IUPAC naming is the process of naming the chemical compounds. These names are published in the Nomenclature of Organic Chemistry (Blue book). On the other hand, the zoological taxonomic naming system is used for naming the animals. The International Code of Zoological Naming has published many research works related to zoological naming.

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Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other h

11Alexandr11 [23.1K]

Complete question:

Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other has carbon tetrachloride as the solvent. Determine that molal concentration, m (or b), and boiling point, Tb.

benzene boiling point=80.1 Kb=2.53

carbon tetrachloride boiling point=76.8 Kb=5.03

Answer:

m = 1.32 mol/kg

Boiling point: 83.4°C

Explanation:

When a nonvolatile solute is added to a pure solvent, the boiling point of the solvent increases, a phenomenon called ebullioscopy. This happens because of the interactions between the solute and the solvent. The temperature variation (new boiling point - normal boiling point) can be calculated by:

ΔT = m*Kb*i

Where m is the molal concentration (moles o solute/mass of solvent in kg), Kb is the ebullioscopy constant of the solvent, and i is the van't Hoff factor, which indicates how much of the solute dissociates. Let's assume that i is equal in both solvents and equal to 1 (the solvent dissociates completely)

Calling the new boiling point as Tb, for benzene:

Tb - 80.1 = m*2.53*1

Tb = 2.53m + 80.1

For carbon tetrachloride:

Tb - 76.8 = m*5.03*1

Tb = 5.03m + 76.8

Because Tb and m are equal for both:

5.03m + 76.8 = 2.53m + 80.1

2.5m = 3.3

m = 1.32 mol/kg

So, substituting m in any of the equations (choosing the first):

Tb = 2.53 * 1.32 + 80.1

Tb = 83.4°C

3 0

3 years ago

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Ai giúp em giải thích cơ chế điều chế phẩm màu diazo và phản ứng ghép đôi với ạ . em xin cám ơn

yuradex [85]

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3 years ago

A measure of kinetic energy of particle motion within a substance is_____.

Allushta [10]

A measure of kinetic energy of particle motion within a substance is temperature.

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3 years ago

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The reaction of pyrrole with bromine forms predominantly __________. View Available Hint(s) The reaction of pyrrole with bromine

xenn [34]

Answer:

a) 2-bromopyrrole

Explanation:

Our options for this questions are:

a) 2-bromopyrrole

b) 2,3-dibromopyrrole

c) N-bromopyrrole

d) 3-bromopyrrole

To understand how the reaction works we have to start with the <u>resonance structures</u>. (Figure 1), on these structures, we will obtain a n<u>egative charge on carbon 2</u> in the pyrrole ring, therefore on this carbon we can generate an attack to an electrophile.

The second step is to check how the mechanism take place. An <u>electrophile is generated</u> by the $Br_2$ and $FeBr_3$ . This electrophile can be <u>attacked</u> by the negative charge on carbon 2 producing the 2-bromopyrrole. (See figure 2).

I hope it helps!

5 0

3 years ago

Determine the pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C. Carry out two c

Nuetrik [128]

The pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C is 101.94atm.

<h3>How to calculate pressure?</h3>

The pressure of an ideal gas can be calculated using the following formula:

PV = nRT

Where;

P = pressure
V = volume
n = number of moles
R = gas law constant
T = temperature

According to information in this question;

T = 25°C = 25 + 273 = 298K
V = 244.6mL = 0.24L
R = 0.0821 Latm/Kmol

P × 0.24 = 1 × 0.0821 × 298

0.24P = 24.47

P = 24.47/0.24

P = 101.94atm

Therefore, the pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C is 101.94atm.

Learn more about pressure at: brainly.com/question/11464844

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