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tankabanditka [31]
3 years ago
11

The area of the base of the regular quadrilateral pyramid is 36 cm2 and the area of a lateral face is 48 cm2. Find: Surface area

of the pyramid
Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
3 0
Surface Area (SA) = Base Area (Ab) + Lateral Area (AL)

Base Area = 36cm^2
Lateral Face Area = 48cm^2

*If this is a quadrilateral pyramid, then it has 4 lateral faces, so just multiply the "one" lateral face by 4.

Lateral Area (AL) = 4 x Lateral Face Area
-> AL = 4 x 48 = 192 cm^2

So:

SA = Ab + AL
-> SA = 36 + 192
-> Surface Area = 228 cm^2
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The unit rates grater than the graph's from small to large are:

y=\frac{13}{6}x             y= \frac{11}{5}x          y = \frac{21}{9}x          y = \frac{19}{8}x

m=\frac{13}{6}              m= \frac{11}{5}           m = \frac{21}{9}            m = \frac{19}{8}

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