How many cl- ions are there in 2. 50 kg of barium chooride.

Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s

bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

$k=\frac{0.693}{t_{1/2}}$

where,

$t_{1/2}$ = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

$k=\frac{0.693}{9}=0.077s^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$ ......(1)

where,

k = rate constant = $0.077s^{-1}$

t = time taken for decay process = 50.7 sec

$[A_o]$ = initial amount of the reactant = ?

[A] = amount left after decay process = 0.0741 M

Putting values in equation 1, we get:

$0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}$

$[A_o]=3.67M$

Now, calculating the time taken by using equation 1:

$[A]=0.0055M$

$k=0.077s^{-1}$

$[A_o]=3.67M$

Putting values in equation 1, we get:

$0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s$

Hence, the time taken by the reaction is 84.5 seconds

6 0

3 years ago

Ten lab safety rules

Bogdan [553]

Don't touch your eyes.

Never taste-test unless the teacher tells you to.

Do not touch anything without directions.

Wear safety goggles.

Wash your hands after each experiment.

Wear proper lab clothes.

Do not mishandle lab equipment.

Clean up your workplace.

Act serious; no horseplay!

Report accidents to the teacher right away!

Have a great day, scholar!

4 0

3 years ago

What are three Possible overlaps that can occur during bond formation

mart [117]

Answer:

The Sigma (σ) Bond

S-S Overlapping. In this kind of overlapping, one 's' orbital from each participating atom undergoes head-on overlapping along the internuclear axis. ...

S-P Overlapping. ...

P-P overlapping.

4 0

2 years ago

A salt bridge is used to provide electrons a path to flow from the electrode of one half-cell to another. TRUE FALSE

kicyunya [14]

It is false. The salt bridge is not a path for electrons, but a path for ions to flow from one half-cell to another. It help to balance the charge between the oxidation and reduction vessels.

8 0

3 years ago

For many years chloroform (CHCl3) was used as an inhalation anesthetic in spite of the fact that it is also a toxic substance th

Debora [2.8K]

Hey there!:

Molar mass:

CHCl3 = ( 12.01 * 1 )+ (1.008 * 1 ) + ( 35.45 * 3 ) => 119.37 g/mol

C% = ( atomic mass C / molar mass CHCl3 ) * 100

For C :

C % = (12.01 / 119.37 ) * 100

C% = ( 0.1006 * 100 )

C% = 10.06 %

For H :

H% = ( atomic mass H / molar mass CHCl3 ) * 100

H% = ( 1.008 / 119.37 ) * 100

H% = 0.008444 * 100

H% = 0.8444 %

For Cl :

Cl % ( molar mass Cl3 / molar mass CHCl3 ):

Cl% = ( 3 * 35.45 / 119.37 ) * 100

Cl% = ( 106.35 / 119.37 ) * 100

Cl% = 0.8909 * 100

Cl% = 89.9%

Hope that helps!

4 0

3 years ago