So to solve problems like these you can work out each equation by substituting the x and y with the coords from the vertex (2,-4) and which ever one is true is the corresponding equation.
Lets try the first one
A) y = 2( x-2)^2-4 this would become
-4 = 2(2-2)^2-4 we solve this and get
-4 = 2(0)-4
-4 = -4
so it seems like A is the correct answer, of course we'd wanna check out the other answers just to be sure.
Lets try one and do C
C) -2 = 2(-4-2)^2+2
-2 = 2(-8)^2+2
-2 = 130
These aren't equal so this can't be our equation
So you can also do one more just to be super sure you have the right answer but I think A is the correct one :)
Answer:
5832 ways
Step-by-step explanation:
Since the circle has 8 sectors and there is 4 colour,
Assuming the sectors are numbered 1 to 8,
Sector 1 : can be coloured with any of the 4 colour in 4 ways
Sector 2 can be coloured with any of the remaining 3 colours in 3 ways
Sector 3 in 3 ways without using the colour in sector 2
Sector 4 in 3 ways without using the colour in sector 3
Sector 5 in 3 ways without using the colour in sector 4
Sector 6 in 3 ways without using the colour in sector 5
Sector 7 in 3 ways without using the colour in sector 6
Sector 8 in 2 ways without using the colours in sector 1 and 7
Number of ways of colouring = 4*3*3*3*3*3*3*2 = 5832 ways
I dont know if you know this, but there are 3 different 3's. So how can we figure out the question if we don't know which one is underlined?
