Answer : The amount of heat released, 45.89 KJ
Solution :
Process involved in the calculation of heat released :

Now we have to calculate the amount of heat released.
where,
Q = amount of heat released = ?
m = mass of water = 27 g
= specific heat of liquid water = 4.184 J/gk
= specific heat of solid water = 2.093 J/gk
= enthalpy change for fusion = 40.7 KJ/mole = 40700 J/mole
conversion :
Now put all the given values in the above expression, we get
(1 KJ = 1000 J)
Therefore, the amount of heat released, 45.89 KJ
The answer is C. <span>The density of the fluid is greater than the density of the object.</span>
Answer:
D.) small, dense negative nucleus surrounded by a diffuse positively charged cloud
Explanation:
I am not 100% sure but the reason I think this is the answer is because Protons and Neutrons are in the nucleus. Protons being positively charged and neutrons being negatively charged. Again, I do not know for sure, but I think D is the answer.