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ZanzabumX [31]
2 years ago
15

What orbital type is being filled throughout the transition metal B Groups?

Chemistry
1 answer:
Nataliya [291]2 years ago
8 0

Answer:

The correct answer is: d-orbital

Explanation:

The transition metals are the chemical elements that belong to the B-group of the periodic table, from group 1B to 8B. The B-group is located between the groups IIA and IIIA in the periodic table.

The general electronic configuration of the chemical elements belonging to this group is (n-1) d¹⁻¹⁰ ns⁰⁻², because of the <u>partially filled d-subshell</u> in the ground state or excited state. <u>Therefore, the transition metals are refereed as the </u><u>d-block elements</u><u>.</u>

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How many moles of atoms are contained in 15.7 g of Bromine
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1 mol of Br = 79.9 g

15.7 g / 79.9 g = 0.196 moles of atoms
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Electron A falls from energy level X to energy level Y and releases blue light. Electron B falls from energy level Y to energy l
MrMuchimi

Answer: Transition from X to Y will have greater energy difference.

Explanation: For studying the energy difference, we require Planck's equation.

                                E=\frac{hc}{\lambda}

where, h = Planck's Constant

c = Speed of light

E = Energy

\lambda = Wavelength of particle

From the equation, it is visible that the energy and wavelength follow inverse relation which means that with low wavelength value, energy will be the highest and vice-versa.

As electron A falls from X-energy level to Y-energy level, it releases blue light which has low wavelength value (around 470 nm) which means that it has high energy.

Similarly, Electron B releases red light when it falls from Y-energy level to Z-energy level, which has high wavelength value (around 700 nm), giving it a low energy value.

Energy Difference between X-energy level and Y-energy level will be more.


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What is the strongest intermolecular force
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Which field of science studies the composition and structure of matter?
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If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of H2SO4(aq)? For your ans
Alik [6]

Question is incomplete, complete question is;

A 34.8 mL solution of H_2SO_4 (aq) of an unknown concentration was titrated with 0.15 M of NaOH(aq).

H_2SO_4(aq)+2NaOH(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)

If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of H_2SO_4(aq)? For your answer, only type in the numerical value with two significant figures. Do NOT include the unit.

Answer:

0.044 M is the molarity of H_2SO_4(aq).

Explanation:

The reaction taking place here is in between acid and base which means that it is a neutralization reaction .

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_1,M_2\text{ and }V_2  are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=34.8 mL\\n_2=1\\M_2=0.15 M\\V_2=20.4 mL

Putting values in above equation, we get:

2\times M_1\times 34.8 mL=1\times 0.15 M\times 20.4 mL\\\\M_1=\frac{1\times 0.15 M\times 20.4 mL\times 10}{2\times 34.8 mL}=0.044 M

0.044 M is the molarity of H_2SO_4(aq).

4 0
3 years ago
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