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egoroff_w [7]
3 years ago
8

What did Ernest Rutherford s gold foil experiment demonstrate about atoms?

Chemistry
1 answer:
mote1985 [20]3 years ago
6 0
Rutherford performed gold foil experiment to understand that how negative and positive particles could Co exist in an atom. He bombarded alpha particles on a 0.00004 cm thick gold foil.

He proposed a planetary model of the atom and concluded following results and demonstrated that,
1. An atom produces a line spectrum.
2. An Electron revolves around the nucleus without any orbits.
3. Since most of the particles passed through the foil undeflected it means that most of the volume occupied by an atom is empty.
4. An Atom as a whole is neutral.
5. The deflection of few particles on the foil suggested that there is center of positive particles in an atom called the nucleus of the atom.
6. The complete rebounce of few particles on the gold foil suggested that the nucleus is very dense and hard.
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A weather balloon was initially at a pressure of 0.900 atm, and its volume was 35.0 L. The pressure decreased to 0.750 atm, with
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Boyle's Law

P₁V₁=P₂V₂

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3 0
1 year ago
A popular car has a gas tank that holds a maximum of 14.5 gallons of fuel. What is
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Taking into account the change of units, the size of the tank is 54.88 liters.

In first place, the rule of three is a tool used to quickly solve problems involving a proportional relationship between two variables.

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other), the direct rule of three should be applied.

The rule of three is applied as follows, with A, B and C being known values ​​and D being an unknown value: if A maintains a certain relationship with B, and it is known that C and D have the same relationship, it is possible to calculate the unknown value D using the following expression:

D=\frac{CxB}{A}

In this case, the rule of three can be applied as follows: if 1 gallon is equal to 3.785 liters, 14.5 gallons are equal to how many liters?

D=\frac{14.5 gallonsx3.785 liters}{1 gallon}

Solving:

D= 54.88 liters

In summary, the size of the tank is 54.88 liters.

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D - for example, Potassium has 1 electron on its outer shell, whilst Chlorine has 7 electrons on its outer shell. Potassium loses one electron to Chlorine so that each of them have a full outer shell. This would form Potassium Chloride.
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Explanation:

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Which element is used in light bulbs as filament
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