Answer:
To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest
Options are as follow,
A) <span>Constant volume, no intermolecular forces of attraction,energy loss in collisions
B) </span><span>No volume, strong intermolecular forces of attraction, perfectly elastic collisions
C) </span><span>Constant volume, no intermolecular forces of attraction, energy gain during collisions
D) </span><span>No volume, no intermolecular forces of attraction, perfectly elastic collisions
Answer:
Option-D (</span>No volume, no intermolecular forces of attraction, perfectly elastic collisions) is the correct answer.
Explanation:
As we know there are no interactions between gas molecules due to which they lack shape and volume and occupies the shape and volume of container in which they are kept. So, we can skip Option-B.
Secondly we also know that the gas molecules move randomly. They collide with the walls of container causing pressure and collide with each other. And these collisions are perfectly elastic and no energy is lost or gained during collisions. Therefore Option-A and C are skipped.
Now we are left with only Option-D, In option D it is given that ideal gas has no volume. This is true related to Ideal gas as it is stated in ideal gas theories that molecules are far apart from each other and the actual volume of gas molecules compared to volume of container is negligible. Hence, for ideal gas Option-D is a correct answer.
When ammonium chloride NH4Cl is added to water and stirred, it dissolves spontaneously (this is the basis for ΔG) for and the resulting solution feels cold (endothermic, the basis for ΔH). Without doing any calculations, we can easily deduce the signs of ΔG, ΔH, and ΔS for this process based on the observations.
ΔG < 0 (it is spontaneous)
ΔH < 0 (because the process is endothermic - it absorbs energy)
ΔS > 0 (entropy increases because of the dissolution of NH4Cl in water
1) Balanced chemical reaction
H2SO4 (aq) + 2NaOH(aq) ----> Na2SO4(aq) + 2 H2O(liq)
2) Molar ratios
1 mol H2SO4 : 2 mol NaOH : 1 mol Na2SO4
3) Number of moles of NaOH
M = n / V => n = M * V = 1.0 M * 0.018 liter = 0.018 mol
of NaOH.
4) Determine the number of moles of H2SO4 using proportionality
1 mol H2SO4 / 2 mol NaOH = x / 0.018 mol NaOH
Solve for x:
x = 0.018 mol NaOH * 1 mol H2SO4 / 2 mol NaOH =0.009 mol H2SO4
5) Calculate the molarity using 0.009 mol and 25 mililiters
M = n / V = 0.009 mol / 0.025 liter = 0.36 M
Answer: the concentration of the H2SO4 is 0.36 M
Solube is able to dissolve to certain extent usually in reference to water
