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snow_lady [41]
3 years ago
14

How much heat is absorbed by 41 g iron skillet when its temperature varies from 9°C. to 20°C

Physics
1 answer:
alexgriva [62]3 years ago
4 0

Answer:

202.95J

Explanation:

The formulae for the energy absorbed by the iron skillet is;

q=m*c*ΔФ   where q=energy absorbed, m is mass of iron skillet, c is specific heat capacity and ΔФ is change in temperature

Given that;

m= 41g

ΔФ=20°-9°=11°

c=0.45 J/g°C

q= 41×0.45×11

q= 202.95 J

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Answer:

A) The resonance angular frequency in an L-R-C circuit is

\omega_0 = \frac{1}{\sqrt{LC}} = \frac{1}{\sqrt{0.45\times0.36\times 10^{-6}}}\\\omega_0 = 2.48\times10^3 rad/s

B) The current can be found by calculating the impedance of the system.

Z = \sqrt{R^2 + (X_L - X_C)^2} = R

Since X_L = X_C at resonance.

So, I = V/Z = V/R = 30 / 100 = 0.3A

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What is the layers of the earth and which one is made up of liquid?
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Answer:

The outter core

Explanation:

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A car travels at a constant velocity of 70 mph for one hour. At the second hour, the car’s velocity was 60 mph. At the third hou
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When the velocity increases, then the acceleration will be positive and when the velocity decrease then the acceleration will be negative.

During the first hour, the velocity was 70 mph and during the seconds hour the velocity was 60 mph. Hence, the velocity decrease in the seconds hour. So, the acceleration will be negative during the second hour.

Now, during the third hour the velocity increases as it is 80 mph. Hence, the acceleration will be positive during the third hour.


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An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time
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Explanation:

Distance = (intial speed)X(Time) + 1/2(acceleration)X(Time) [Third equation of motion]

As initial speed is zero, therefore;

Distance = 1/2(acceleration)X(Time)

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              = 1/2 (90)

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Hence, the object traveled 45 meters.

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A proton having an initial velvocity of 20.0i Mm/s enters a uniform magnetic field of magnitude 0.300 T with a direction perpend
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R=\frac{1.6*10^{-27} * 20*10^{6}}{1.6*10^{-19}*0.3 }

R =66.67× 10^{-2}

Hence, the radius of curvature of the proton's path while in the field is 66.67 × 10^{-2}.

<h3>What do you mean by Magnetic field?</h3>

The magnetic influence on moving electric charges, electric currents and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.  The magnetic field of a permanent magnet pulls on ferromagnetic substances like iron and attracts or repels other magnets. A magnetic field that varies with location will also exert a force on a variety of non-magnetic materials by changing the velocity of those particles' outer electrons. Electric currents, like those utilized in electromagnets, and electric fields that change in time produce magnetic fields that surround magnetized things.

To know more about Magnetic Field visit:

brainly.com/question/14848188

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