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snow_lady [41]
3 years ago
14

How much heat is absorbed by 41 g iron skillet when its temperature varies from 9°C. to 20°C

Physics
1 answer:
alexgriva [62]3 years ago
4 0

Answer:

202.95J

Explanation:

The formulae for the energy absorbed by the iron skillet is;

q=m*c*ΔФ   where q=energy absorbed, m is mass of iron skillet, c is specific heat capacity and ΔФ is change in temperature

Given that;

m= 41g

ΔФ=20°-9°=11°

c=0.45 J/g°C

q= 41×0.45×11

q= 202.95 J

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Two charges, q1 and q2, are separated by a certain distance r. if the magnitudes of the charges are halved and their separation
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Andrea and Chuck are riding on a merry-go-round. Andrea rides on a horse at the outer rim of the circular platform, twice as far
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a)

The angular speed of Andrea and Chuck is the same.

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The merry go round is a rigid body, so all its point cover the same angular displacement in the same time: this means that it doesn't matter where Andrea and Chuck are located along the merry-go-round, their angular speed will still be the same.

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r is the distance from the centre of rotation

Here let's call r_c the distance at which Chuck is rotating, so his tangential speed is

v_c = \omega r_c

Now we know that Andrea is rotating twice as far from the centre, so at a distance of

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So his tangential speed is

v_a = \omega r_a = \omega (2 r_c) = 2(\omega r_c) = 2 v_c

So, Andrea's tangential speed is twice the value of Chuck's tangential speed.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

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