If a 2,000-kg car hits a tree with 500 n of force over a time of 0.5 seconds, what is the magnitude of its impulse?
2 answers:
You might be interested in
Answer:
Explanation:
It is a question relating to charging of capacitor . For charging of capacitor , the formula is as follows.
Q = CV ( 1 - )
λ = 1/CR , C is capacitance and R is resistance.
= 1/(500 x 10⁻⁶ x 20 x 10³ )
= .1
λ t = .1 x 20
λ t = 2
CV = 500 X 10⁻⁶ X 5
= 2500 X 10⁻⁶ C
Q = 2500 x 10⁻⁶ ( 1 - )
= 2500 x 10⁻⁶ x .86566
= 2161.66 μ C .
voltage = Charge / capacitor
2161.66 μ C / 500μ F
= 4.32 V
Answer:
When I got this question I had to draw it out so if you have to do that, draw 3 stick figures holding hands, one representing the mother, father, and daughter. Then you write their weights on top of them and then draw an arrow pointing from the father to the mother.
Explanation:
use this formula :
=
then you fill it in :
=
=
=
then you multiply that with the daughters weight :
and that's the answer :) : 37.89N