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Delvig [45]
3 years ago
11

An object moves in a circle of radius R at constant speed with a period T . If you want to change only the period in order to cu

t the object's acceleration in half, the new period should be
Physics
1 answer:
GarryVolchara [31]3 years ago
5 0
The answer to that is three
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9. A plane starts at rest & accelerates along the ground before takeoff. It
Phoenix [80]

Answer:

  9.877 m/s^2

Explanation:

The acceleration can be computed from ...

  d = (1/2)at^2

  (1600 m) = (1/2)a(18 s)^2

  a = (1600/162) m/s^2 ≈ 9.877 m/s^2

6 0
3 years ago
What comes down but never goes up
White raven [17]

Answer:

Explanation:

rain and your age

5 0
2 years ago
What is the speed of a wave in (m/s) with a 5 meter wavelength and a period of 20 seconds?
arlik [135]

Answer: 0.25 m/s

Explanation:  Speed = wavelengt · frequency  

v = λf   and frequency is 1/period  f = 1/T

Then v = λ/T = 5 m / 20 s = 0.25 m/s

6 0
2 years ago
A red cross helicopter takes off from headquarters and flies 120 km at 70 degrees south of west. There it drops off some relief
fiasKO [112]

Answer:

130 km at 35.38 degrees north of east

Explanation:

Suppose the HQ is at the origin (x = 0, y = 0)

So the coordinates of the helicopter after the 1st flight is

x_1 = -120cos70^o = -41.04 km

y_1 = -120sin70^o = -112.763 km

After the 2nd flight its coordinate would be:

x_2 = x_1 - 75sin60^o = -41.04 - 64.95 = -106km

y_2 = y_1 + 75cos60^o = -112.763 + 37.5 = -75.263 km

So in order to fly back to its HQ it must fly a distance and direction of

s = \sqrt{y_2^2 + x_2^2} = \sqrt{75.263^2 + 106^2} = \sqrt{5664.519169 + 11236} = \sqrt{16900.519169} = 130 km

tan\theta = \frac{y_2}{x_2} = \frac{75.263}{106} = 0.71

\theta = tan^{-1}0.71 = 0.62 rad \approx 35.38^o north of east

3 0
2 years ago
What style of art represents people or objects exactly as they appear in life?
frozen [14]
REALISM shows things as they REALLY look.
5 0
3 years ago
Read 2 more answers
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