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cupoosta [38]
3 years ago
12

Open the site in your browser. (If any pop-up windows appear, think about what they indicate about the web site before you close

them.) Skim the article. Think about whether you trust the information presented or whether you have doubts about some of it. On a scale of 0 to 6, where 6 is the most trustworthy, how would you rate this site? (Note that all responses will be marked as "correct" at this point.)
Computers and Technology
1 answer:
kati45 [8]3 years ago
5 0

Answer:

The answer to the given question is 5-6 (trustworthy).

Explanation:

When visits any web site there are several information is given, We click on it shows some pop-up box. it is smaller than the whole windows. for example, If we want to download any free software. So we go on a software site and choose the version for software and click for download. when we click on download there is a pop-up window open to provide the details of the software and has a one-button when we click on the button it downloads the software. If we cancel the pop-up window by click on the cancel /close (X) button it will close the window.

So the pop-up windows are very trustworthy.

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Assign decoded_tweet with user_tweet, replacing any occurrence of 'TTYL' with 'talk to you later'. Sample output with input: 'Go
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Answer:

I am going to use the Python programming language to answer this. The source code is given below:

print("Enter your tweet here")

user_tweet = input()

decoded_tweet = user_tweet.replace('TTYL', 'talk to you later')

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print(decoded_tweet)

Explanation:

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Attached is the screenshot of the output.

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Write a Python function to determine the volume of material remaining after the hole is drilled. The function should take as inp
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Answer:

height = int(input ("Enter height : ") )

print (height)

width = int( input("Enter length : ") )

print (width)

half_width =width/2

half_height=height/2

while 0==0:

   radius = float( input("Enter radius : ") )

   print (radius)

   

   if radius<half_width and radius <half_height:

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def remainingVolume(height,width,radius):

       

   vol_box=height*width*width

   print (vol_box)

   vol_hole=3.14178*radius*radius*height

   print (vol_hole)

   

   remaining_vol=vol_box-vol_hole

   print ("Remaining volume is ",remaining_vol)

   

remainingVolume(height,width,radius);

Explanation:

Take input from user for height ,width and radius. To find volume of box formula is vol=height* width*length\\

Let's assume width and length is same so

length= width

Using this formula of box volume find box volume.Now find volume of hole.

Consider hole as small cylinder, find volume of cylinder and subtract from volume of box to get remaining volume of box after hole.

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