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liberstina [14]
3 years ago
9

Please help me with this! (: I would appreciate it very much!!

Chemistry
2 answers:
telo118 [61]3 years ago
8 0

Answer:

A D E B C F

Explanation:

mrs_skeptik [129]3 years ago
7 0

Answer:

I'm still learning but I wish I knew the answer to it.

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The illustration on the left represents a mixture of H2 (light blue) molecules and O2 (red) molecules. If these were to react to
kvasek [131]

Answer:

6 molecules of H2O are the maximum number.

Explanation:

From the drawing it can be seen that there are 6 H2 molecules and 3 O2 molecules reacting, which can be represented by the following chemical equation

6 H2 + 3 O2 ⇒ H2O

This equation is not balanced, so we proceed to balance it, being as follows:

6 H2 + 3 O2 ⇒ 6H2O

With which it can be determined that a maximum of 6 H2O molecules can be formed.

4 0
4 years ago
What is the ph of a 0.085 m solution of nitrous acid (hno2) that has a ka of 4.5 × 10-4?
True [87]
Data Given:
                  Molarity  =  0.085 M

                  Ka  =  4.5 × 10⁻⁴
To Find:
                  pH  =  ?
Solution:
             First find out the concentration of [H⁺] Ions using following formula,

                 [H⁺]  =  \sqrt{Ka . M}

Puting values,

                 [H⁺]  =  \sqrt{0.00045 * 0.085}

                 [H⁺]  =  \sqrt{0.00003825}

                 [H⁺]  =  <span>0.00618465843
</span>Or,
                 [H⁺]  =  6.18 × 10⁻³

Calculate pH as,

                 pH  =  -log [H⁺]

                 pH  =  -log (6.18 × 10⁻³)

                 pH  =  2.20
3 0
4 years ago
Five kilograms of liquid carbon tetrachloride undergo a mechanically reversible, isobaric change of state at 1 bar during which
Drupady [299]

Answer:

Explanation:

From the information given:

Mass of carbon tetrachloride = 5 kg

Pressure = 1 bar

The given density for carbon tetrachloride = 1590 kg/m³

The specific heat of carbon tetrachloride =  0.84 kJ/kg K

From the composition, the initial volume of carbon tetrachloride will be:= \dfrac{5 \ kg }{1590 \ kg/m^3}

= 0.0031 m³

Suppose \beta is independent of temperature while pressure is constant;

Then:

The change in volume can be expressed as:

\int ^{V_2}_{V_1} \dfrac{dV}{V} =\int ^{T_2}_{T_1} \beta dT

In ( \dfrac{V_2}{V_1})  = \beta (T_2-T_1)

V_2 = V_1 \times exp (\beta (T_2-T_1))

V_2 = 0.0031 \ m^3  \times exp  (1.2 \times 10^{-3} \times 20)

V_2 = 0.003175 \ m^3

However; the workdone = -PdV

W = -1.01 \times 10^5 \ Pa \times ( 0.003175 m^3 - 0.0031 \ m^3)

W = - 7.6 J

The heat energy Q = Δ h

Q = mC_p(T_2-T_1)

Q = 5 kg \times 0.84 \ kJ/kg^0 C \times 20

Q = 84 kJ

The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;

ΔU = ΔQ + W

ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)

ΔU = 83.992 kJ

3 0
3 years ago
Which statement is in accordance with the steady state model of the universe?
Sloan [31]

E. The nuclear fuel in the stars will eventually burn out, making the universe a cold and dark place

7 0
3 years ago
How many moles of koh are needed to neutralize 0.4 moles of hno3
Julli [10]

Answer:

0.4 moles of KOH is required to neutralize 0.4 moles of HNO3.

Explanation:

The equation of the reaction is

KOH(aq) + HNO3(aq) ------> KNO3(aq) + H2O(l)

This is a neutralization reaction. A neutralization reaction is a reaction between an acid and a base to form salt and water only.

Having written the balanced chemical reaction equation, we can now solve the prob!em stoichiometrically.

From the balanced reaction equation;

1 mole of KOH is required to neutralize 1 mole of HNO3

Therefore x moles of KOH is required to neutralize 0.4 moles of HNO3

x= 1×0.4/1 = 0.4 moles

Therefore, 0.4 moles of KOH is required to neutralize 0.4 moles of HNO3.

7 0
3 years ago
Read 2 more answers
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