Answer:
6 molecules of H2O are the maximum number.
Explanation:
From the drawing it can be seen that there are 6 H2 molecules and 3 O2 molecules reacting, which can be represented by the following chemical equation
6 H2 + 3 O2 ⇒ H2O
This equation is not balanced, so we proceed to balance it, being as follows:
6 H2 + 3 O2 ⇒ 6H2O
With which it can be determined that a maximum of 6 H2O molecules can be formed.
Data Given: Molarity = 0.085 M
Ka = 4.5 × 10⁻⁴
To Find: pH = ?
Solution: First find out the concentration of [H⁺] Ions using following formula,
[H⁺] = 
Puting values,
[H⁺] =

[H⁺] =

[H⁺] = <span>0.00618465843
</span>Or,
[H⁺] = 6.18 × 10⁻³Calculate pH as,
pH = -log [H⁺]
pH = -log (6.18 × 10⁻³)
pH = 2.20
Answer:
Explanation:
From the information given:
Mass of carbon tetrachloride = 5 kg
Pressure = 1 bar
The given density for carbon tetrachloride = 1590 kg/m³
The specific heat of carbon tetrachloride = 0.84 kJ/kg K
From the composition, the initial volume of carbon tetrachloride will be:
= 0.0031 m³
Suppose
is independent of temperature while pressure is constant;
Then:
The change in volume can be expressed as:





However; the workdone = -PdV

W = - 7.6 J
The heat energy Q = Δ h


Q = 84 kJ
The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;
ΔU = ΔQ + W
ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)
ΔU = 83.992 kJ
E. The nuclear fuel in the stars will eventually burn out, making the universe a cold and dark place
Answer:
0.4 moles of KOH is required to neutralize 0.4 moles of HNO3.
Explanation:
The equation of the reaction is
KOH(aq) + HNO3(aq) ------> KNO3(aq) + H2O(l)
This is a neutralization reaction. A neutralization reaction is a reaction between an acid and a base to form salt and water only.
Having written the balanced chemical reaction equation, we can now solve the prob!em stoichiometrically.
From the balanced reaction equation;
1 mole of KOH is required to neutralize 1 mole of HNO3
Therefore x moles of KOH is required to neutralize 0.4 moles of HNO3
x= 1×0.4/1 = 0.4 moles
Therefore, 0.4 moles of KOH is required to neutralize 0.4 moles of HNO3.