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Irina18 [472]
4 years ago
5

What is the molar mass of Cu(OH)2

Chemistry
1 answer:
Mice21 [21]4 years ago
6 0

Answer:

97.54

Explanation:

Molar mas of cu (oh) 2

Cu = 63.54

O x 2  = 16 x 2 = 32

H x 2 = 1 x 2 = 2

TOTAL = 97.54

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How many particles are in on mole?
shusha [124]

The answer is 1023 particles

6 0
3 years ago
Balance the following chemical equation by providing the correct coefficients fe+h2so4 fe(so4)3 + h2
Dmitriy789 [7]

Answer:

2Fe + 3H2SO4 + Fe2(SO4)3+ 3H2

Explanation:

1. Fe (SO4) 3 is an incorrectly written formula because iron is trivalent as we can see by this three ahead of SO4. SO4 is divalent always.

2. since (SO4) is 3, this three shows us that there must be 3 in the reactants as well.

so now there is 3H2SO4

3. Since we have added 3 to one hydrogen we must add another. So now it's 3H2

4. and finally iron. In Fe2 (SO4) 3 we see this 2 in front of Fe which means it goes 2Fe.

3 0
3 years ago
Which total mass of iron is necessary to produce 1.00 mole of copper?
Harman [31]
1 mole Fe produces 1 mole Cu 
<span> molar mass of Fe is 55.8 g / mole 
 
answer: </span><span>55.8g</span>
4 0
4 years ago
Why a neutral atom has the same number of protons and electrons
Alex777 [14]

Explanation:

When an atom has an equal number of electrons and protons, it has an equal number of negative electric charges (the electrons) and positive electric charges (the protons). The total electric charge of the atom is therefore zero and the atom is said to be neutral. ... Chemically, we say that the atoms have formed bonds.

5 0
4 years ago
Night visin cameras are sensitive to energies around 2.21 x 10-19 J. What wavelength of electromagnetic radiation do they use?
defon

Answer:

8.99×10^-7m

Explanation:

The wavelength can be calculated using the expression below

E=hcλ

Where E= energy= 2.21 x 10^-19 J.

C= speed of light= 3x10^8 m/s

h= planks constant= 6.626 × 10^-34 m2 kg / s

E=hcλ

λ= E/(hc)

Substitute for the values

λ=( 2.21 x 10^-19 )/(6.626 × 10^-34 × 3x10^8 )

= 8.99×10^-7m

6 0
3 years ago
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