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3 years ago

Why do an atoms electrons revolve around its proton instead of drifting away?

Chemistry

1 answer:

WINSTONCH [101]3 years ago

8 0

Answer:

Electrons are pulled to the nucleus by gravity. The modern atomic model describes the electrons as moving around the nucleus like a cloud, rather than in perfect orbits. I think atoms and protons attract but i'm not 100% sure on that haha. I hope this helps you out :)

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mote1985 [20]

Answer:

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2 years ago

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What is the symbol, atomic number, atomic mass, # of protons, # of neutrons, # of electrons, ion charge for the beryllium ion?

jolli1 [7]

Answer:

Symbol Be

atomic number 4

protons 4

neutrons 5

electrons 4

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Explanation:

Look at the periodic table and all the answers can be found there. If you would like to learn how to find them please message me below.

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4 years ago

What is the purpose of the flame that is lit below a hot air balloon

SashulF [63]

Answer:

A hot air balloon uses a burner to heat up the air inside the balloon. The burner is usually fueled by liquid propane. The burner mixes the fuel with air and ignites the mixture, which creates a flame directly underneath the bottom opening of the hot air balloon. Once the air inside the balloon begins to get warm, the balloon will rise. The pilot controls the balloon’s altitude by releasing hot air from a vent at the top of the balloon, releasing the warmer air causes the balloon to descend.

Explanation:

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3 years ago

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Sulfur dioxide, SO 2 ( g ) , can react with oxygen to produce sulfur trioxide, SO 3 ( g ) , by the reaction 2 SO 2 ( g ) + O 2 (

aleksley [76]

<u>Answer:</u> The amount of heat produced by the reaction is -21.36 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]$

For the given chemical reaction:

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(SO_3(g))})]-[(2\times \Delta H_f_{(SO_2(g))})+(1\times \Delta H_f_{(O_2(g))})]$

We are given:

$\Delta H_f_{(SO_2(g))}=-296.8kJ/mol\\\Delta H_f_{(SO_3(g))}=-395.7kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(2\times (-395.7))]-[(2\times (-296.8))+(1\times (0))]\\\\\Delta H_{rxn}=-197.8kJ/mol$

To calculate the number of moles, we use ideal gas equation, which is:

$PV=nRT$

where,

P = pressure of the gas = 1.00 bar

V = Volume of the gas = 2.67 L

n = number of moles of gas = ?

R = Gas constant = $0.0831\text{ L. bar }mol^{-1}K^{-1}$

T = temperature of the mixture = $25^oC=[25+273]K=298K$

Putting values in above equation, we get:

$1.00bar\times 2.67L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1\times 2.67}{0.0831\times 298}=0.108mol$

To calculate the heat released of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

q = amount of heat released = ?

n = number of moles = 0.108 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = -197.8 kJ/mol

Putting values in above equation, we get:

$-197.8kJ/mol=\frac{q}{0.108mol}\\\\q=(-197.8kJ/mol\times 0.108mol)=-21.36kJ$

Hence, the amount of heat produced by the reaction is -21.36 kJ

3 0

3 years ago

Why do you think the Na+ ion is smaller than a neutral Na atom? Why do you think the Cl - ion is larger than a neutral Cl atom?

Sphinxa [80]

Answer:

Na+ ion is smaller than a neutral Na atom in the ion there was one more proton which will attract electron bring it closer to the center making the atomic radius smaller. Therefore making a Na+ ion is smaller than a neutral Na atom Explanation:

yes

7 0

3 years ago