Answer:
Kc = 0.20
Explanation:
N₂O₄ ⇄ 2NO₂
moles 5.3mol 2.3mol
Vol 5L 5L
Molarity 5.3/5M 2.3/5M
= 1.06M = 0.46M
Kc = [NO₂]²/[N₂O₄] = (0.46)²/(1.06) = 0.1996 ≅ 0.20
<span>134 ml
First, let's determine how many moles of oxygen we have.
Atomic weight oxygen = 15.999
Molar mass O2 = 2*15.999 = 31.998 g/mol
We have 3 drops at 0.050 ml each for a total volume of 3*0.050ml = 0.150 ml
Since the density is 1.149 g/mol, we have 1.149 g/ml * 0.150 ml = 0.17235 g of O2
Divide the number of grams by the molar mass to get the number of moles
0.17235 g / 31.998 g/mol = 0.005386274 mol
Now we can use the ideal gas law. The equation
PV = nRT
where
P = pressure (1.0 atm)
V = volume
n = number of moles (0.005386274 mol)
R = ideal gas constant (0.082057338 L*atm/(K*mol) )
T = Absolute temperature ( 30 + 273.15 = 303.15 K)
Now take the formula and solve for V, then substitute the known values and solve.
PV = nRT
V = nRT/P
V = 0.005386274 mol * 0.082057338 L*atm/(K*mol) * 303.15 K / 1.0 atm
V = 0.000441983 L*atm/(K*) * 303.15 K / 1.0 atm
V = 0.133987239 L*atm / 1.0 atm
V = 0.133987239 L
So the volume (rounded to 3 significant figures) will be 134 ml.</span>
The volume increases and the final volume is 2.1 L
<h3>Why volume increases?</h3>
The volume of a gas is directly related to the heat and pressure. If temperature increases, volume increases.
If pressure increases, volume decreases
Based on Boyle's law,
The absolute temperature of a gas is directly proportional to the volume of the gas.
As the balloon change increases its temperature, the volume increases
The Boyle's equation is:
V₁T₂ = V₂T₁
Where,
- V is volume
- T is absolute temperature of 1, initial state and 2, final state of the gas.
Replacing :
V₁ = 2.0L
T₂ = 35°C + 273.15 = 308.15K
V₂ = ?
T₁ = 25°C + 273.15 = 298.15 K
2.0L x 308.15 K = V₂ x 298.15 K
2.1 L = V₂
Final volume is 2.1L
Hence, The volume increases and the final volume is 2.1 L
Learn more about gas laws here ;
brainly.com/question/12669509
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