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3 years ago

14.

Chemistry

1 answer:

crimeas [40]3 years ago

3 0

Answer:

Jeweler B = more accurate

Jeweler A = more precise

Error:

0.008, 0

% error :

0.934% ; 0

Explanation:

Given that:

True mass of nugget = 0.856

Jeweler A: 0.863 g, 0.869 g, 0.859 g

Jeweler B: 0.875 g, 0.834 g, 0.858 g

Official measurement (A) = 0.863 + 0.869 + 0.859 = 2.591 / 3 = 0.864

Official measurement (B) = 0.875 + 0.834 + 0.858 = 2.567 / 3 = 0.8556

Accuracy = closeness of a measurement to the true value

Accuracy = true value - official measurement

Jeweler A's accuracy :

0.856 - 0.864 = - 0.008

Jeweler B's accuracy :

0.856 - 0.856 = 0.00

Therefore, Jeweler B's official measurement is more accurate as it is more close to the true value of the gold nugget.

However, Jeweler A's official measurement is more precise as each Jeweler A's measurement are closer to one another than Jeweler B's measurement which are more spread out.

Error:

Jeweler A's error :

0.864 - 0.856 = 0.008

% error =( error / true value) × 100

% error = (0.008/0.856) × 100% = 0.934%

Jeweler B's error :

0.856 - 0.856 = 0 ( since the official measurement as been rounded to match the decimal representation of the true value)

% error = 0%

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2 years ago

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3 years ago

An aqueous solution contains 0.23 M potassium hypochlorite.

Arturiano [62]

Answer:

0.22 mol HClO, 0.11mol HBr.

0.25mol NH₄Cl, 0.12 mol HCl

Explanation:

A buffer is defined as a mixture in solution between weak acid and its conjugate base or vice versa.

Potassium hypochlorite (KClO) could be seen as conjugate base of HClO (Weak acid). That means the addition of 0.22 mol HClO will convert the solution in a buffer. HBr reacts with KClO producing HClO, thus, 0.11mol HBr will, also, convert the solution in a buffer. 0.23 mol HBr will react completely with KClO and in the solution you will have only HClO, no a buffering system.

Ammonia (NH₃) is a weak base and its conjugate base is NH₄⁺. That means the addition of 0.25mol NH₄Cl will convert the solution in a buffer. Also, NH₃ reacts with HCl producing NH₄⁺. Thus, addition of 0.12 mol HCl will produce NH₄⁺. 0.25mol HCl consume all NH₃.

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3 years ago

It takes 2,267 joules of heat to raise the temperature of a 44.5 gram sample of a metal from 33.9°C to 288.3°C. What is the heat

ehidna [41]

Answer:

$\boxed{\text{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}}}$

Explanation:

The formula for the amount heat q absorbed by a substance is

q = mcΔT

where

m = the mass of the substance

C = the specific heat capacity of the material

ΔT = the temperature change

Data:

q = 2267 J

m = 44.5 g

T₁ = 33.9 °C

T₂ = 288.3 °C

Calculations:

ΔT = (288.3 - 33.9) °C = 254.4 °C

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$\text{The specific heat capacity of the metal is \boxed{\textbf{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}}}$

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irina1246 [14]

Answer:

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Explanation:

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