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mojhsa [17]
4 years ago
7

Nancy needs to do a scientific investigation for her class. She is interested in pottery, plants, and basketball. Which of the f

ollowing questions would be suitable for use in a scientific investigation?
A. What length of time is best to use for the firing of pottery to make it strong?
B. What is the most number of points ever scored in a professional basketball game?
C. How many needles grow on the giant redwoods in California?
D. What color of carnation flowers do people find most attractive?
Physics
2 answers:
JulijaS [17]4 years ago
7 0
I believe that the answer is A hope this helped.
il63 [147K]4 years ago
3 0

Answer:

A. What length of time is best to use for the firing of pottery to make it strong?

Explanation:

Point A

What length of time is best to use for the firing of pottery to make it strong?

This is a scientific question for Nancy since while making pots from black mud, it is very important to know how much time is required to fire the pot in order to make it strong. Because if we fire it for too long the pot may be become too hot and will eventually crack. While if we fire for less time it will not become hard enough to withstand its shape. So knowing the proper time to fire the pot is very essential in pottery.

Point B, Point C and Point D are not scientific investigations since it includes ones likes and dislikes, quantities and numbers of goal scored which is not scientific.

Hence, option A is the correct answer.

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Choose all that represent ways that Venus is different than Earth.
Ganezh [65]

The answer is C because carbon dioxide is trapped in a thick atmosphere.

7 0
4 years ago
Light of wavelength 650 nm is normally incident on the rear of a grating. The first bright fringe (other than the central one) i
koban [17]

Answer:

A

   N  = 1340.86 \ slits  / cm

B

    \theta  = 15.7^o

Explanation:

From the question we are told that  

      The wavelength is  \lambda  =  650 \  nm  =  650  *10^{-9} \  m  

        The angle of  first bright fringe is  \theta  =  5^o  

        The order of the fringe considered is  n  =1

Generally the condition for constructive interference is  

       dsin (\theta ) = n * \lambda

=>    d =  \frac{1 *  650 *10^{-9 }}{ sin(5)}

=>    d = 7.458 *10^{-6} \  m

Converting to cm

           d = 7.458 *10^{-6} \  m = 7.458 *10^{-6}  * 100 =  0.0007458 \  cm

Generally the number of grating pre centimeter is  mathematically represented as

           N  =  \frac{1}{d}

=>         N  =  \frac{1}{0.0007458}

=>         N  = 1340.86 \ slits  / cm

Considering question B  

   From the question we are told that

     The first wavelength is  \lambda_1 =  650 \ nm  =  650 *10^{-9} \  m

     The second wavelength is  \lambda_2 = 429 \  m   =   420 *10^{-9 } \  m

      The order of the fringe is  n  =  2

       The grating is  N =  5000 \  slits / cm

Generally the slit width is mathematically represented as

              d =  \frac{1}{N  }

=>          d =  \frac{1}{ 5000  }

=>          d =   0.0002 \  c m  =  2.0 *10^{-6} \ m

Generally the condition for constructive interference for the first ray is mathematically represented as

         d sin(\theta_1) =  n *  \lambda_1

=>      \theta_1 = sin^{-1} [\frac{ 2 *  \lambda }{d}]

=>       \theta_1 = sin^{-1} [\frac{ 2 *   650 *10^{-9} }{ 2*10^{-6}}]

=>        \theta_1 = 40.5 ^o

Generally the condition for constructive interference for the second ray is mathematically represented as

         d sin(\theta_2) =  n *  \lambda_2

=>      \theta_2 = sin^{-1} [\frac{ 2 *  \lambda_1 }{d}]

=>       \theta_2 = sin^{-1} [\frac{ 2 *   420 *10^{-9} }{ 2*10^{-6}}]

=>        \theta_2 = 24.8  ^o

Generally the angular separation is mathematically represented as

            \theta  =  \theta_1 - \theta_1

=>          \theta  = 42.5^o -  24.8^o

=>          \theta  = 15.7^o

4 0
3 years ago
Roaring of a lion is different from the sound of the mosquito why?​
Soloha48 [4]

Answer:

The roaring of the lion is louder and has low pitch than the sound produced by a mosquito. Hence, they sound so different

4 0
3 years ago
How much heat is necessary to change 350 g of ice at -20 degrees Celsius to water at 20 Celsius?
sergejj [24]

Answer:

160790 J

Explanation:

We can find the heat necessary for the ice to go from -20 degrees Celsius to 0 degrees Celsius:

Q=mc\Delta t

Where c=2.09 J/g^{\circ}C is the specific heat of ice, that is the amount of heat that must be supplied per unit mass to raise its temperature in a unit.

Q=(350g)(2.09 J/g^{\circ}C)(0^{\circ}C-(-20^{\circ}C))=14630 J

We must calculate the latent heat of fusion required for this ice mass to change to water:

Q=mH

Where H=334 J/g is the specific latent heat of fusion of water, that is the amount of energy needed per unit mass of a substance at its melting point to change from the solid to the liquid state.

Q=(350g)(334 J/g)=116900 J

Then we calculate the heat necessary for the water to go from 0 degrees Celsius to 20 degrees Celsius:

Q=mc\Delta t

Where c=4.18 J/g^{\circ}C is the specific heat of water, that is the amount of heat that must be supplied per unit mass to raise its temperature in a unit.

Q=(350g)(4.18 J/g^{\circ}C)(20^{\circ}C-0^{\circ}C)=29260 J

Finally the 3 results are added:

Q_{T}=14630 J + 116900 J + 29260 J=160790 J

6 0
3 years ago
A pulley system used to lift car tires has a mechanical advantage of 11.2. If you pull on the pulley with a force of 150 N, how
Novay_Z [31]
1680 is the answer i got because i did this problem in apex
7 0
3 years ago
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