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Galina-37 [17]
3 years ago
6

Level 3- How is tooth decay related to pH?How can it be prevented?

Chemistry
2 answers:
uranmaximum [27]3 years ago
4 0

Answer:

A lower pH of the mouth creates bad bacteria that eventually lead to decay of the tooth.  

It can be prevented by avoiding food that causes acidity.

Explanation:

svlad2 [7]3 years ago
4 0

Tooth decay is caused by the pH level in the mouth dropping below 5.5, meaning it is acidic. It can be prevented by brushing your teeth as toothpaste is an alkali which will neutralise the pH level in your mouth.

Hope this helps

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This is a mixture that has different properties throughout.
Olin [163]

Answer:

Heterogenous mixture is a mixture that has different properties throughout.

Explanation:

Mixture refers to substances that are not chemically mixed together, that is, they can easily be separated by physical methods. There are two major types of mixture; these are heterogeneous and homogeneous mixtures. Homogeneous mixtures refer to those mixtures that are uniform in composition. A good example of this is tap water. Heterogeneous mixture on the other hand refers to those mixtures, which are not uniform in composition. A good example of this is a mixture of water and sand.  

4 0
3 years ago
The following reaction shows the products when sulfuric acid and aluminum hydroxide react.
SSSSS [86.1K]

Answer:

There will remain 11.47 grams of Al(OH)3

Explanation:

Step 1: Data given

Mass of sulfuric acid = 35.0 grams

Molar mass sulfuric acid = 98.08 g/mol

Mass of aluminium hydroxide = 30.0 grams

Molar mass of aluminium hydroxide = 78.0 g/mol

Step 2: The balanced equation

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles Al(OH)3 = 30.0 grams / 78.0 g/mol

Moles Al(OH)3 = 0.385 moles

Moles H2SO4 = 35.0 grams / 98.08 g/mol

Moles H2SO4 = 0.357 moles

Step 4: Calculate the limiting reactant

For 2 moles Al(OH)3 we need 3 moles H2SO4 to produce 1 mol Al(SO4)3 and 6 moles H20

H2SO4 is the limiting reactant. It will completely be consumed ( 0.357 moles). Al(OH)3 is in excess. There will be react 2/3 * 0.357 = 0.238 moles

There will remain 0.385 - 0.238 = 0.147 moles

Mass of Al(OH)3 remaining = 0.147 moles* 78.0 g/mol = 11.47 grams

There will remain 11.47 grams of Al(OH)3

6 0
3 years ago
The kinetic molecule theory assumes that the particles of an ideal gas​
eduard

Explanation:

It is assumed that the particles of an ideal gas have no such attractive forces. The motion of each particle is completely independent of the motion of all other particles. The average kinetic energy of gas particles is dependent upon the temperature of the gas.

8 0
3 years ago
The reaction of Cr2O3 with silicon metal at high temperatures will make chromium metal. 2CrO3(s) + 3Si(s)----> 4Cr(l) + 3SiO2
nalin [4]

Answer: 51.45 grams of excess reagent is left after the completion of reaction.

Explanation: For the calculation of moles, we use the formula:

Moles=\frac{\text{Given mass}}{\text{Molar mass}}     ....(1)

  • For Si

Given mass = 92 grams

Molar mass = 28g/mol

Putting values in equation 1, we get:

Moles=\frac{92g}{28g/mol}=3.285moles

  • For Cr_2O_3

Given mass = 112 grams

Molar mass = 116g/mol

Putting values in equation 1, we get:

Moles=\frac{112g}{116g/mol}=0.965moles

The reaction follows:

2Cr_2O_3(s)+3Si(s)\rightarrow 4Cr(l)+3SiO_2(s)

By Stoichiometry,

2 moles of Cr_2O_3 reacts with 3 moles of silicon

So, 0.965 moles of Cr_2O_3 reacts with = \frac{3}{2}\times 0.965 = 1.4475 moles of Silicon.

As, the moles of silicon is more than the required amount and is present in excess.

So, the excess reagent for the reaction is Silicon.

Moles of silicon remained after reaction = 3.285 - 1.4475 = 1.8375 moles

To calculate the amount of Silicon left in excess is calculated by using equation 1:

1.8375=\frac{\text{Given mass}}{28}

Amount of Silicon in excess will be 51.45 grams.

5 0
4 years ago
A helium balloon has a volume of 36 L. The pressure of the helium gas in the balloon is 132 kPa and its temperature is 27 degree
Verdich [7]

Answer:

n =1.905mol

Explanation:

Hello!

In this case, by considering helium gas as an ideal one, we can use the following equation:

PV=nRT

Whereas P should go in atmospheres and T in Kelvins; thus we proceed as follows:

n=\frac{PV}{RT}=\frac{132kPa*\frac{1atm}{101.325kPa}*36L}{0.08206\frac{atm*L}{mol*K}(27+273)K} =1.905mol

Best regards!

3 0
3 years ago
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