Answer:
0.492 J/g °C
General Formulas and Concepts:
<u>Thermodynamics</u>
Specific Heat Formula: q = mcΔT
- <em>q</em> is heat (in J0
- <em>m</em> is mass (in g)
- <em>c</em> is specific heat (in J/g °C)
- <em>ΔT</em> is change in temperature (in °C)
Explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] <em>q</em> = 45.0 J
[Given] <em>m</em> = 8.10 g
[Given] <em>ΔT</em> = 24.3 °C - 13.0 °C = 11.3 °C
[Solve] <em>c</em>
<em />
<u>Step 2: Solve for </u><em><u>c</u></em>
- Substitute in variables [Specific Heat Formula]: 45.0 J = (8.10 g)c(11.3 °C)
- Multiply: 45.0 J = (91.53 g °C)c
- Isolate <em>c</em>: 0.491642 J/g °C = c
- Rewrite: c = 0.491642 J/g °C
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.491642 J/g °C ≈ 0.492 J/g °C
Answer: <em>Acceleration of the ball in the given system is 5 meter per Second Square</em>
<em>The laws of motion are used to determine various aspects of an object in motion</em>.
Explanation:
Applying the first law of motion to calculate acceleration; if formula used in first law is given as
Here we have a final velocity as 40 meter per second and initial velocity as 20 meter per second and time span is given as 2 second applying the given values in the given equation and finding the value of a
Answer:
0.319 gram
Explanation:
Convert Normality to Molarity.
for NaOH: 0.1068 N = 0.1068 M
Citric acid contains 3 groups of COOH so that 1 mole of citric acid reacts with 3 moles of NaOH.
#moles of NaOH = Concentration x Volume = 0.1068 x 46.65 x 10^-3
= 4.98 x 10^-3 mol
#moles of Citric acid = #moles of NaOH/3 = 1.66 x 10^-3 mol
mass of citric acid = mole x molar mass = 1.66 x 10^-3 x 192 = 0.319 gram
Answer:
This question appears incomplete
Explanation:
This question appears incomplete because of the absence of options. However, hydrogen is placed in group 1 because it has just one electron in it's outermost shell (which happens to be the only shell it has) just like every other group 1A/group 1 element. While helium is placed in group 8A/group 18 because it has a completely filled outermost shell (which is also the only shell it has) just like every other element in group 8A/group 18.