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natali 33 [55]
3 years ago
7

In the periodic table hydrogen is placed in Group 1A (group 1) and helium is placed in Group 8A (group 18). The most likely reas

on for this is:
Chemistry
1 answer:
Alexus [3.1K]3 years ago
8 0

Answer:

This question appears incomplete

Explanation:

This question appears incomplete because of the absence of options. However, hydrogen is placed in group 1 because it has just one electron in it's outermost shell (which happens to be the only shell it has) just like every other group 1A/group 1 element. While helium is placed in group 8A/group 18 because it has a completely filled outermost shell (which is also the only shell it has) just like every other element in group 8A/group 18.

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A 140.0-g sample of water at 25.0°C is mixed with 108.6 g of a certain metal at 100.0°C. After thermal equilibrium is establishe
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Answer:

The value of specific heat of metal = 0.3537 \frac{KJ}{Kg K}

Explanation:

Mass of water m_{w} = 140 gm = 0.14 kg

Initial temperature of water T_{w} = 25°c = 298 K

Mass of metal m_{metal} = 108.6 gm = 0.1086 kg

Initial temperature of metal T_{metal} = 100°c = 373 K

After thermal equilibrium the final temperature  T_{f} = 29.6°c = 302.6 K

Apply energy principal

Heat lost by metal = heat gain by water  --------- (1)

⇒ Heat lost by metal = m_{metal} × C_{metal} × ( T_{metal} - T_{f} )

⇒ Heat lost by metal = 0.1086 × C_{metal} × ( 373 -302.6 )

⇒ Heat lost by metal = C_{metal} × 7.64544  KJ -------- (2)

Now

Heat gain by water = m_{w} × C_{water} × ( T_{f} - T_{w} )

⇒ Heat gain by water = 0.14 × 4.2 × ( 302.6 - 298)

⇒ Heat gain by water = 2.7048 KJ --------------------- (3)

From the energy principal

Equation 2 = equation 3

C_{metal} × 7.64544  = 2.7048

C_{metal} = 0.3537 \frac{KJ}{Kg K}

This is the value of specific heat of metal.

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