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Y_Kistochka [10]
2 years ago
5

Marine fossils belonging to the early Cenozoic era are found only in the southern parts of Mississippi. What does this evidence

say about the state during this period?
A) The state was flooded by tropical seas during this period.
B) The northern parts of the state were probably above sea level.
C) The Mississippi River had a different course during this period.
D) The marine animals did not like the weather in the northern parts. 
 PLZZZZZ HELP 20 POINTS 
Chemistry
2 answers:
bulgar [2K]2 years ago
7 0
I say B because of the Pangaea. And Mississippi probably looked different. Sorry If I am wrong but I am pretty sure this is correct. I have this question to on a recent quiz  <span />
zmey [24]2 years ago
3 0
Yes i believe the answer is B
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How are covalent compounds similar to acids?
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Answer:

Acids are substances that produce an create high amounts of H+ ions when dissolved in water. And because the hydrogen bond's with non-metals,it forms covalent bonds. So,all acids are covalent bonds.

Explanation:

Colavent compounds are colavent bonds

Source:

https://www.quora.com/Are-acids-covalent-compound

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Androstenedione, which contains only carbon, hydrogen, and oxygen, is a steroid hormone produced in the adrenal glands and the g
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Answer: The molecular formula for androstenedione is, C_{19}H_{26}O_2

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=5.527g

Mass of H_2O=1.548g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 5.527 g of carbon dioxide, \frac{12}{44}\times 5.527=1.507g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 1.548 g of water, \frac{2}{18}\times 1.548=0.172g of hydrogen will be contained.

For calculating the mass of oxygen:

Mass of oxygen in the compound = (1.893g)-[(1.507g)+(0.172g)]=0.214g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.507g}{12g/mole}=0.126moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.172g}{1g/mole}=0.172moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.214g}{16g/mole}=0.0133moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0133 moles.

For Carbon = \frac{0.126}{0.0133}=9.5

For Hydrogen  = \frac{0.172}{0.0133}=12.9\approx 13

For Oxygen  = \frac{0.0133}{0.0133}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 9.5 : 13 : 1

To make in a whole number we are multiplying the ratio by 2, we get:

The ratio of C : H : O = 19 : 26 : 2

Thus, the empirical formula for the given compound is C_{19}H_{26}O_2

The empirical formula weight of C_{19}H_{26}O_2 = 19(12) + 26(1) + 2(16) = 286 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{286.4}{286}=1

Molecular formula = C_{19}H_{26}O_2

Therefore, the molecular formula for androstenedione is, C_{19}H_{26}O_2

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Answer:

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