Question

A person on a road trip drives a car at different constant speeds over several legs of the trip. She drives for 10.0 min at 50.0 km/h, 19.0 min at 100.0 km/h, and 60.0 min at 55.0 km/h and spends 40.0 min eating lunch and buying gas. What is the average speed for the entire trip (

Answer 1

The average speed for the entire trip is 47.5 m/s .

It is given that for different time span car have different speed and also the person spend $40\ min=\dfrac{40}{60}\ hrs =0.67\ hrs\ .$ in eating lunch and buying gas.

We know , average speed is total distance covered by total time taken .

Therefore , average speed , $v=\dfrac{total\ distance }{total\ times}$

$v=\dfrac{\dfrac{10}{60}\times 50+\dfrac{19}{60}\times 100+\dfrac{60}{60}\times 55}{\dfrac{10}{60}+\dfrac{10}{60}+\dfrac{60}{60}+ \dfrac{40}{60}}\\\\\\v=47.5\ m/s$

Hence, this is the required solution.

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