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Vlad [161]
3 years ago
6

A person on a road trip drives a car at different constant speeds over several legs of the trip. She drives for 10.0 min at 50.0

km/h, 19.0 min at 100.0 km/h, and 60.0 min at 55.0 km/h and spends 40.0 min eating lunch and buying gas. What is the average speed for the entire trip (
Physics
1 answer:
irakobra [83]3 years ago
7 0
<h2>The average speed for the entire trip is 47.5 m/s .</h2>

It is given that for different time span car have different speed and also the person spend 40\ min=\dfrac{40}{60}\ hrs =0.67\ hrs\ . in eating lunch and buying gas.

We know , average speed is total distance covered by total time taken .

Therefore , average speed , v=\dfrac{total\ distance }{total\ times}

v=\dfrac{\dfrac{10}{60}\times 50+\dfrac{19}{60}\times 100+\dfrac{60}{60}\times 55}{\dfrac{10}{60}+\dfrac{10}{60}+\dfrac{60}{60}+ \dfrac{40}{60}}\\\\\\v=47.5\ m/s

Hence, this is the required solution.

Learn More :

Average speed

https://brainly.in/question/12701198

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With fuel prices for combustible engine automobiles increasing, researchers and manufacturers have given more attention to the c
Alinara [238K]

Answer:

Then the difference of weight between the two cars are:

Δw = 14210 - 5292 = 8918 N

Explanation:

An object's weigh due to the gravitational attraction force of the earth is:

w = mg

            Where: m is the object's mass

                         g is the  gravitational acceleration in the surface earth

                         g = 9.8 m/s2

The the ultralight car's weight is:

w_{uc} = (540)(9.8)

w_{uc} = 5292 N

And the Honda Accord's weight is:

w_{HA} = (1450)(9.8)

w_{HA} = 14210 N

Then the difference of weight between the two cars are:

Δw = 14210 - 5292 = 8918 N

4 0
3 years ago
If the mass of the sun is 1x, at least one planet will fall into the habitable zone if I place a planet in orbits___, ____, ____
nasty-shy [4]

If the mass of the sun is 1x, at least one planet will fall into the habitable zone. if I place a planet in orbits 2, 6, and 75, and all planets will orbit the sun successfully.

If the mass of the sun is 2x, at least one planet will fall into the habitable zone. if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully.

If the mass of the sun is 3x, at least one planet will fall into the habitable zone if I place a planet in orbits 672, and 7 and all planets will orbit the sun successfully.

8 0
2 years ago
What is the mass of an object that is accelerated at 25 m/s2 by a force of 135 N?
yKpoI14uk [10]

Answer:

<h3>The answer is 5.4 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{135}{25}   =  \frac{27}{5} \\

We have the final answer as

<h3>5.4 kg</h3>

Hope this helps you

4 0
3 years ago
A cyclist going downhill is accelerating at 1. 2 m/s2. If the final velocity of the cyclist is 16 m/s after 10 seconds, what is
mel-nik [20]

Answer:

\boxed {\boxed {\sf v_i= 4 \ m/s}}

Explanation:

We are asked to find the cyclist's initial velocity. We are given the acceleration, final velocity, and time, so we will use the following kinematic equation.

v_f= v_i + at

The cyclist is acceleration at 1.2 meters per second squared. After 10 seconds, the velocity is 16 meters per second.

  • v_f= 16 m/s
  • a= 1.2 m/s²
  • t= 10 s

Substitute the values into the formula.

16 \ m/s = v_i + (1.2 \ m/s^2)(10 \ s)

Multiply.

16 \ m/s = v_i + (1.2 \ m/s^2 * 10 \ s)

16 \ m/s = v_i + 12 \ m/s

We are solving for the initial velocity, so we must isolate the variable v_i. Subtract 12 meters per second from both sides of the equation.

16 \ m/s - 12 \ m/s = v_i + 12 \ m/s -12 \ m/s

4 \ m/s = v_i

The cyclist's initial velocity is <u>4 meters per second.</u>

6 0
2 years ago
What happens to the force between the spheres when you increase the mass of one of the spheres?
andrew11 [14]

The force between the spheres increases when the mass increases in one of the spheres.

<u>Explanation:</u>

            Newton law of universal gravity extends gravity beyond the earth's surface. This gravity depends directly on the mass of both objects and is inversely proportional to square of distance between their centers.  

                   \bold{F=\frac{G \times\left(m_{1} \times m_{2}\right)}{\left(r^{2}\right)}}

          Since gravity is directly proportional to “mass of both interacting objects”, stronger objects with greater gravitational force attract. If the mass of one object increases, gravity between them also increases. For example, if an object's mass of one double, force between them also doubles.  

4 0
3 years ago
Read 2 more answers
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