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brilliants [131]
3 years ago
8

Time (min)

Physics
1 answer:
charle [14.2K]3 years ago
8 0

Answer:

rgvdghrryyrfgtr was the other monkey that I have to do with my best pet peeve for the rest and neon scooter is my friend is giving her the money for your cuz to be a good offer tho it was a great idea for a while and then she said yes and she is a great person ever and she was madly happy I have to go soon to be honest with me if she wants me back to my base or not but she wasnt it to be honest with her but

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The star Vega has an apparent visual magnitude of 0.03, and the star HR 4374 has an apparent visual magnitude of 4.87. It has be
laila [671]

Answer:

(D) Vega must produce more energy than HR 4374.

Explanation:

The apparent visual magnitude is defined as the luminosity of a star seen from earth. The Greek astronomer Hipparcos was the first who invent a numerical scale to describe how bright a star appear to be in the sky to the naked eye, so he gave an apparent magnitude of 6 to the faintest star in the sky and an apparent magnitude of 1 to the brigthest one. Since the arrive of the telescope era this range was expanded to negative numbers for the most luminous one.

The human eye has a logaritmical response to the luminosity of stars, so as an example, if one star has an apparent magnitude of 6 and another one has an apparent magnitude of 1, the second one will be 100 times brigther than the first one. In the other hand, for a star that has apparent magnitude of 1 it will appear to be 2.512 times brigther than a star with apparent magnitude of 2.

The apparent magnitude of a star can variate as a consecuence of the distance from earth or for its energy production.

With all these facts clear enough described above, it is easier to conclude that as the two star are at the same distance the apparent visual magnitude will depend in the energy production. In the case of Vega it has an apparent visual magnitude of 0.03, while HR 4374 has an apparent visual magnitude of 4.87. According with the scale stablished for Hipparcos, Vega will be more luminous than HR 4374. This means that Vega produce more energy than HR 4374.

8 0
3 years ago
A wire with a circular cross section and a resistance R is lengthened to 9.66 times its original length by pulling it through a
damaskus [11]

Answer:

The resistance of the wire after it is stretched is 93.31R.

Explanation:

Resistance is the property of the material to oppose the current flow through it. It is given by the relation :

R = (ρl)/A

Here ρ is resistivity, l is length of wire and A is the area of the wire.

Let l₀, and A₀ are the original length and original circular cross section area of the wire. while l₁ and A₁ are the new length and new circular cross section area of the wire.

Volume of the original wire, V₀ = A₀ x l₀

Volume of the new wire, V₁ = A₁ x l₁

According to the problem. volume remain same. So,

V₀ = V₁

A₀ x l₀ = A₁ x l₁

It is given that l₁ = 9.66 x l₀. Substitute this value in the above equation;

A₀ x l₀ = A₁ x 9.66 x l₀

A₁ = A₀/9.66

Resistance of the original wire, R = (ρl₀)/A₀

Resistance of the new wire, R₁ = (ρl₁)/A₁

Substitute the value of l₁ and A₁ in the above equation.

R₁ = (ρ x l₀ x 9.66)/(A₀/9.66) = 93.31 x (ρl₀)/A₀

But (ρl₀)/A₀ = R. hence,

R₁ = 93.31 R

8 0
3 years ago
A 36,287 kg truck has a momentum of 907,175 kg • m/s. What is the trucks velocity.
Airida [17]

Momentum = Mass x Velocity

Put the values where they belong and solve for Velocity.

In this case, since Mass is being multiplied by Velocity, to solve for be Velocity you would divide both sides by Velocity.  The velocity will equal the momentum divided by the mass.

4 0
4 years ago
Sawyer launches his 180 kg raft on the Mississippi River by pushing on it with a force of 75N. How long must Sawyer push on the
Daniel [21]

Answer: 4.8 s

Explanation:

We have the following data:

m=180 kg the mass of the raft

F=75 N the force applied by Sawyer

V=2 m/s the raft's final speed

V_{o}=0 m/s the raft's initial speed (assuming it starts from rest)

We have to find the time t

Well, according to Newton's second law of motion we have:

F=m.a (1)

Where a is the acceleration, which can be expressed as:

a=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{t-t_{o}} (2)

Substituting (2) in (1):

F=m\frac{V-V_{o}}{t-t_{o}} (3)

Where t_{o}=0

Isolating t from (3):

t=\frac{m(V-V_{o})}{F} (4)

t=\frac{180 kg(2 m/s-0 m/s)}{75 N}

Finally:

t=4.8 s

6 0
3 years ago
a bicyclist initially at rest speeds up steadily during this time interval she averages 3.50 miles per second determine the init
Kobotan [32]

Answer:

Explanation:

Given parameters:

Average speed  = 3.5miles per second

Unknown:

Initial speed  = ?

Average speed  = ?

Final speed in the interval = ?

Solution:

Since the bicyclist started from rest and speeds up steadily, it is correct to assume that her starting or initial speed is 0m/s.

At a state of rest, a body has no speed.

Average speed is the sum total of the speed covered at each time interval. This value is given already to be 3.5miles per second.

Final speed is the speed before the bicycle halts. This speed will be the same as the average speed here which is 3.5miles per second.

Speed is the rate of change of distance with time.

7 0
3 years ago
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