Answer: Option b, 4410 meters.
Explanation: If there is no air resistance, the acceleration experienced by the raindrop is equal to the gravitational acceleration:
a = -9.8m/s^2
for the velocity, we integrate over time, and there is no constant because we don't have initial velocity.
v = - (9.8m/s^2)*t
For the position, we integrate again over time, and we add a constant of integration that will be equal to the initial height of the raindrop.
r = (-9.8m/s^2)(t^2)/2 + H
if at t= 30s the raindrop reaches the ground, we have that:
r(30) = 0 = (-4.9*900)m + H
H = 4.9*900m = 4410m
So the initial height of the raindrop s 4410 meters.