Answer:
The force on the proton will be twice in comparison with the force experienced by the electron.
Explanation:
The magnetic force acting on the moving charge particle is perpendicular to the velocity as well as the magnetic field. The factors upon which the magnitude of the force is depending and proportional are as follows:
1 Magnitude of the charge particle.
2 Magnitude of the velocity of moving charge.
3 Magnitude of magnetic field.
4 Sine of angle between the velocity and magnetic field.
As far as direction is concerned, it can be find out by right hand rule.
Lets consider,
Speed of electron = Ve
Speed of proton vp= 2ve
Magnitude of the force F = qvBsin∅
Force acting on electron Fe = qe.ve.Bsin∅
Force acting on proton Fp = qp.vp.Bsin∅
Fp = -2 qe.ve.Bsin∅
Fp = -2Fe
Negative sign shows the direction of Force on proton is opposite to the direction of force on electron.
Answer:
The finger has to be placed at 5.25cm
Explanation:
The steps and appropriate formula in musical instrument is as shown in the attachment.
Answer:
(a) Final speed of block = 3.2896 m/s
(b) 6.7350 m/s is the speed of the bullet-block center of mass?
Explanation:
Given that:
Mass of bullet (m₁) = 6.20 g
Initial Speed of bullet (u₁) = 929 m/s
Final speed of bullet (v₁) = 478 m/s
Mass of wooden block (m₂) = 850g
Initial speed of block initial (u₂) = 0 m/s
Final speed of block (v₂) = ?
<u>By the law of conservation of momentum as:</u>
<u>m₁×u₁ + m₂×u₂ = m₁×v₁ + m₂×v₂</u>
6.20×929 + 850×0 = 6.20×478 + 850×v₂
Solving for v₂, we get:
<u>v₂ = 3.2896 m/s</u>
Let the V be the speed of the bullet-block center of mass. So,
V = [m₁* u₁]/[m₁ + m₂] (p before collision = p after collision)
= [6.2 *929]/[5.2+850]
<u>V = 6.7350 m/s
</u>
Answer: The correct answer is option (D).
Explanation:
The area under the line is 10 meters that is displacement which means that area enclosed by the right angled triangle is 10 unit squares.
So, the it can be written as:
Hence the, the correct answer is option (D).
