<h2>
Hello there! :)</h2>
It's very wonderful to help you today!
Answer:
The resistance of the wire after being heated is approximately 1.15 times the resistance before being heated.
Explanation:
The resistance of the wire goes up as the temperature goes up.
By Ohm's law, we have the relationship between the resistance of a conductor R, the current flowing through it, I, and the voltage across it, V,
As described, the current through the wire decreases so, to maintain the same voltage, the resistance must increase when the wire is heated. Let's say R1 is the resistance before heating the wire and R2 is the resistance after,
Let's solve for R2,
In this case, I1 = 0.3A and I2 = 0.26A,
Hence, the <u><em>resistance of the wire after being heated is approximately 1.15 times the resistance before being heated.</em></u>
Answer:
See explanation below.
Explanation:
For this case we atart fom the proportional model given by the following differential equation:
And if we rewrite this expression we got:
If we integrate both sides we got:
And using exponential on both sides we got:
Where represent the initial amount for the isotope and t the time in years and A the amount remaining.
If we want to apply a model for the half life we know that after some time definfd the amount remaining is the hal, so if we apply this we got:
We can cancel and we got:
If we solve for k we can apply natural log on both sides and we got:
And that would be our proportional constant on this case.
If we replace this value for k int our model we will see that:
And using properties of logs we can rewrite this like that:
And thats the common formula used for the helf life time.
U = 0, initial velocity
t = 1.85 s, the time of flght
Assume g = 9.8 m/s² and no air resistance
If the velocity of impact is v, then
v = u + gt
v = (9.8 m/s²)*(1.85 s) = 18.13 m/s
Answer: 18.13 m/s
This would be false. hope this helps. good luck :)