Answer:
Here we have the function:
S(t) = 500 - 400*t^(-1)
Then the rate of change at the value t, will be:
S'(t) = dS(t)/dt
This differentiation will be:
S'(t) = -400/t^2
Then:
a) the rate of change at t = 1 is:
S'(1) = -400/1^2 = -400
The rate of change after one year is -400
b) t = 10
S'(10) = -400/10^2 = -400/100 = -4
The rate of change after 10 years is -4, it reduced as the years passed, as expected.
Answer:
5
Step-by-step explanation:
When taking a percent of a number, multiply the number by the percent divided by a hundred:

You get an answer of
5
40=1.5f+2.25c, please mark brainiest and give it a heart (:
Answer:
3/60=1/20
Step-by-step explanation: