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bonufazy [111]
3 years ago
8

What are the adaptions of the tundra

Physics
1 answer:
Mekhanik [1.2K]3 years ago
7 0

Answer: Migration and hibernation

Explanation: look it up ;)

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Johnny travels to the moon explain what will happen to his mass and weight?
zlopas [31]
His weight on the moon would be less due to gravity and i also believe during your time under little gravity your spine decompresses so you get taller <span />
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You are 12 miles north of your base camp when you begin walking north at a speed of 2mph. what is your location, relative to you
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Http://www.calculator.net/pace-calculator.html?ctype=distance&ctime=05%3A00%3A00&cdistance=5&cdistanceunit=Miles&cpace=02%3A00%3A00&cpaceunit=tpm&printit=0&x=87&y=24 a pace calculator
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Two particles in a high-energy accelerator experiment are approaching each other head-on, each with a speed of 0.9520c as measur
Over [174]

Answer:

the magnitude of the velocity of one particle relative to the other is 0.9988c

Explanation:

Given the data in the question;

Velocities of the two particles = 0.9520c

Using Lorentz transformation

Let relative velocity be W, so

v_r = ( u + v ) / ( 1 + ( uv / c²) )

since each particle travels with the same speed,

u = v

so

v_r = ( u + u ) / ( 1 + ( u×u / c²) )  

v_r = 2(0.9520c) / ( 1 + ( 0.9520c )² / c²) )  

we substitute

v_r = 1.904c / ( 1 + ( (0.906304 × c² ) / c²) )  

v_r = 1.904c / ( 1 + 0.906304 )

v_r = 1.904c / 1.906304

v_r = 0.9988c

Therefore, the magnitude of the velocity of one particle relative to the other is 0.9988c

5 0
3 years ago
Find the velocity in m/s of a swimmer who swims 110m toward the shore in 72s
ruslelena [56]
S=Vt
110=V(72)
110/72=V
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4 0
3 years ago
For a caffeinated drink with a caffeine mass percent of 0.65% and a density of 1.00 g/mL, how many mL of the drink would be requ
slava [35]

Explanation:

First we will convert the given mass from lb to kg as follows.

        157 lb = 157 lb \times \frac{1 kg}{2.2046 lb}

                   = 71.215 kg

Now, mass of caffeine required for a person of that mass at the LD50 is as follows.

         180 \frac{mg}{kg} \times 71.215 kg

         = 12818.7 mg

Convert the % of (w/w) into % (w/v) as follows.

      0.65% (w/w) = \frac{0.65 g}{100 g}

                           = \frac{0.65 g}{(\frac{100 g}{1.0 g/ml})}

                           = \frac{0.65 g}{100 ml}

Therefore, calculate the volume which contains the amount of caffeine as follows.

   12818.7 mg = 12.8187 g = \frac{12.8187 g}{\frac{0.65 g}{100 ml}}

                       = 1972 ml

Thus, we can conclude that 1972 ml of the drink would be required to reach an LD50 of 180 mg/kg body mass if the person weighed 157 lb.

5 0
3 years ago
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