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Kruka [31]
2 years ago
8

By using electroscope, if the body is negatively charged then due to electrostatic induction, then on the leaves there will be a

ppear:
(a) both positive and negative charges
(b) negative charge
(c) positive charge
(d) no charge
Physics
2 answers:
Kryger [21]2 years ago
6 0

(b) negative charge

This is the answer

Gnom [1K]2 years ago
5 0
It should be

B)Negative charge

Hope this one helped
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A sled is on an icy (frictionless) slope that is 30° above the horizontal. When a 40-N force, parallel to the incline and direct
son4ous [18]

Answer: 5.8kg

Explanation:

F - mg sinΦ = ma

Given that

M=?

g= 9.8

Φ= 30

a= 2

F= 40 then

40 - 9.8 * m * sin 30 = 2 * m

40 = 2 * m + 9.8 * m * sin 30

40 = (2 + 9.8 * sin 30) m

m = 40 / (2 + 9.8 * 0.5)

m = 40 / (2 + 4.9)

m = 40 / 6.9

m = 5.797kg

m = 5.8kg

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What information can scientists obtian from tree rings
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What information can scientists obtain from tree rings?

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3 years ago
You are trying to find the amount of heat transferred between two substances. In order to do this, you plan
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Answer:

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2 years ago
3. A football is kicked with a speed of 35 m/s at an angle of 40°.
jarptica [38.1K]

a) 22.5 m/s

The initial vertical velocity is given by:

u_y = u sin \theta

where

u = 35 m/s is the initial speed

\theta=40^{\circ} is the angle of projection of the ball

Substituting into the equation, we find

u_y = (35)(sin 40)=22.5 m/s

b) 26.8 m/s

The initial horizontal velocity is given by:

u_x = u cos \theta

where

u = 35 m/s is the initial speed

\theta=40^{\circ} is the angle of projection of the ball

Substituting into the equation, we find

u_x = (35)(cos 40)=26.8 m/s

c) 2.30 s

The time it takes for the ball to reach the maximum heigth can be found by considering the vertical motion only. This is a uniformly accelerated motion (free-fall), so we can use the suvat equation

v_y = u_y + at

where

v_y is the vertical velocity at time t

u_y = 22.5 m/s

a=g=-9.8 m/s^2 is the acceleration of gravity (negative because it is downward)

At the maximum height, the vertical velocity becomes zero, v_y =0; substituting, we find the time t at which this happens:

0=u_y + gt\\t=-\frac{u_y}{g}=-\frac{22.5}{-9.8}=2.30 s

d) 25.8 m

The maximum height can also be found by considering the vertical motion only. We can use the following suvat equation:

s=u_y t + \frac{1}{2}gt^2

where

s is the vertical displacement at time t

u_y = 22.5 m/s

g=-9.8 m/s^2

Substituting t = 2.30 s, we find the displacement at maximum height, so the maximum height:

s=(22.5)(2.30)+\frac{1}{2}(-9.8)(2.30)^2=25.8 m

e) 123.3 m

In order to find how far does the ball lands, we have to consider the horizontal motion.

First of all, the time it takes for the ball to go back to the ground is twice the time needed for reaching the maximum height:

t=2(2.30 s)=4.60 s

Then, we consider the horizontal motion. There is no acceleration along this direction, so the horizontal velocity is constant:

v_x = 26.8 m/s

Therefore, the horizontal distance travelled during the whole motion is

d=v_x t = (26.8)(4.60)=123.3 m

So, the ball lands 123.3 m far from the initial point.

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3 years ago
The brakes exert a 1,951 N force on a car weighing 18,985 N and moving at 12 m/s. The car finally stops. How long (in seconds) d
nata0808 [166]

Answer:20,000

Explanation:

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