Two cars are traveling on a desert road. After 5.0 seconds they are side by side at the next telephone pole.The distance between
1 answer:
The question looks incomplete, but according to the information given above seem like they have <span>identical journeys.
</span>a. the displacement of car A - <span> 65.5 m
</span>b. the displacement of car B - <span>65.5 m
c. average velocir</span>y of A
d. the average velocity of car B has the same.
</span>a. the displacement of car A - <span> 65.5 m
</span>b. the displacement of car B - <span>65.5 m
c. average velocir</span>y of A
d. the average velocity of car B has the same.
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Answer:
F = 3.86 x 10⁻⁶ N
Explanation:
First, we will find the distance between the two particles:
where,
r = distance between the particles = ?
(x₁, y₁, z₁) = (2, 5, 1)
(x₂, y₂, z₂) = (3, 2, 3)
Therefore,
Now, we will calculate the magnitude of the force between the charges by using Coulomb's Law:
where,
F = magnitude of force = ?
k = Coulomb's Constant = 9 x 10⁹ Nm²/C²
q₁ = magnitude of first charge = 2 x 10⁻⁸ C
q₂ = magnitude of second charge = 3 x 10⁻⁷ C
r = distance between the charges = 3.741 m
Therefore,
<u>F = 3.86 x 10⁻⁶ N</u>