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aleksandrvk [35]
3 years ago
6

Two cars are traveling on a desert road. After 5.0 seconds they are side by side at the next telephone pole.The distance between

the poles is 112m.
Identify the following quantities:
a. the displacement of car A after 5.0s
b. the displacement of car B after 5.0s
 c. the average velocity of car A during 5.0s
d. the average velocity of car B during 5.0s
Physics
1 answer:
stira [4]3 years ago
8 0
The question looks incomplete, but according to the information given above seem like they have <span>identical journeys.
</span>a. the displacement of car A - <span> 65.5 m 
</span>b. the displacement of car B  - <span>65.5 m
c. average velocir</span>y of A  65.5 / 5 = 13.1 m/s
d. the average velocity of car B  has the same. 
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Answer:

a)\frac{F_1}{L}=1.95*10^-^5N

b)\frac{F_2}{L}=1.95*10^-^5N

Explanation:

From the question we are told that:

Distance between wires d=32.2

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a)

Generally the equation for Force on l_1 due to I_2 is mathematically given by

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Where

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B_2=\frac{\mu *i_2}{2\pi d}

Therefore

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F_1=I_1(\frac{\mu *i_2*l_1}{2\pi d})L

\frac{F_1}{L} =\frac{4*\pi*10^{-7}*2.75*4.33*100 }{2*\pi*12.2 }

\frac{F_1}{L}=1.95*10^-^5N

b)

Generally the equation for Force on I_2 due to I_1 is mathematically given by

F_2=I_2B_1L

Where

B_1=Magnetic field current by I_2

B_1=\frac{\mu *I_1}{2\pi d}

Therefore

\frac{F_2}{L} =I_2(\frac{\mu *I_1*I_2}{2\pi d})

\frac{F_2}{L}=1.95*10^-^5N

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