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aleksandrvk [35]
3 years ago
6

Two cars are traveling on a desert road. After 5.0 seconds they are side by side at the next telephone pole.The distance between

the poles is 112m.
Identify the following quantities:
a. the displacement of car A after 5.0s
b. the displacement of car B after 5.0s
 c. the average velocity of car A during 5.0s
d. the average velocity of car B during 5.0s
Physics
1 answer:
stira [4]3 years ago
8 0
The question looks incomplete, but according to the information given above seem like they have <span>identical journeys.
</span>a. the displacement of car A - <span> 65.5 m 
</span>b. the displacement of car B  - <span>65.5 m
c. average velocir</span>y of A  65.5 / 5 = 13.1 m/s
d. the average velocity of car B  has the same. 
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Answer:

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7 0
3 years ago
An airplane flies eastward and always accelerates at a constant rate. At one position along its path it has a velocity of 34.3 m
Tomtit [17]

Explanation:

We'll need two equations.

v² = v₀² + 2a(x - x₀)

where v is the final velocity, v₀ is the initial velocity, a is the acceleration, x is the final position, and x₀ is the initial position.

x = x₀ + ½ (v + v₀)t

where t is time.

Given:

v = 47.5 m/s

v₀ = 34.3 m/s

x - x₀ = 40100 m

Find: a and t

(47.5)² = (34.3)² + 2a(40100)

a = 0.0135 m/s²

40100 = ½ (47.5 + 34.3)t

t = 980 s

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inessss [21]

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4 0
3 years ago
Read 2 more answers
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