A student pushes against a wall with a force of 30N. The wall does not move. What amount of force does the wall exert on the stu
2 answers:
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Answer:
The value is
Explanation:
From the question we are told that
The focal length of the objective is
The focal length of the eyepiece is
The tube length is
Generally the magnitude of the overall magnification is mathematically represented as
Where is the objective magnification which is mathematically represented as
=>
=>
is the eyepiece magnification which is mathematically evaluated as
So
Answer:
v_average = 15 m / s
Explanation:
The average speed can be found in two ways,
* taking the distance traveled and divide it by the time spent
* taking the velocities in each time interval and then finding the weighted average by the time fraction
v_average = 1 / t_total ∑ vi ti
Let's apply this last equation
Total time is
t = t₁ + t₂
t = 10 + 10 = 20 min
v_average = 10/20 10 + 10/20 20
v_average = 10/2 + 20/2
v_average = 15 m / s
Answer:
The rod attracts the ball
Explanation:
