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xxMikexx [17]
2 years ago
6

A student pushes against a wall with a force of 30N. The wall does not move. What amount of force does the wall exert on the stu

dent?
A. 0N
B. Less than 30N
C. 30N
D. More than 30N
Physics
2 answers:
True [87]2 years ago
8 0

Answer:

C

Explanation:

they both have to be the same for both to not move

satela [25.4K]2 years ago
7 0

Answer: C,30N

Explanation:

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Why is it important for scientist to do research?
sweet-ann [11.9K]

Answer:

Because if they dont research first they will be unprepared

Explanation:

3 0
3 years ago
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Which of the following statements about this experiment is FALSE? Before each trial one should reshape the bob into something li
Troyanec [42]

Which of the following statements about this experiment is FALSE? Before each trial one should reshape the bob into something like a ball. You may assume the collision between the bob and the box is completely inelastic. The initial position for the box should be just touching the pendulum bob when it is hanging straight down. To make the box move, the pendulum bob should hit close to the bottom of the box during the collision is given below

Explanation:

So, The bob is held at angle theta from initial position, P. Find the displacement from P.  

displacement= L sin  Θ. I hope you get it here. The pendulum forms a triangle with length L, the initial position and horizontal displacement.

So,the point is at displacement point the kinetic energy of bob is 0 and when it is released it will have maximum kinetic energy at P. It will hit the box and all he kinetic energy of bob will get transferred into driving force(F.D) of box. Now kinetic energy = Force * displacement.

K.E= 0.5 m V^2= F.D * Lsin Θ.

Find F.D

F.D = (0.5 m V^2) /  Lsin Θ.

Now for the box, F.D - Friction = m(box) a.

Friction = F.D + m(box) a.

Find the accelaration of box from an equation of motion. ( u=0, find displacement of box,s,time taken and so on)

U get the friction. Now,

coeff of friction = µ = friction/ reaction.

Note that reaction here = weight of box= m(box) g.   g= acc of free fall= 9.81.

So here u go.. U get the coeff of friction.. I hope am right here.. and made no mistake.. Anyway try it with the values to confirm! ;)

7 0
3 years ago
What is the weight of a dog that has a mass of 47.0 kg?​
Nat2105 [25]

Answer:

while we often confuse mass with weight, 47 kg is 47 x 9.8 = 460.6 Newtons. 9.8 is acceleration of gravity in m/sec/sec

8 0
3 years ago
Why is our (a person's) gravitational pull NOT as strong as the Earth's gravitational pull
Bezzdna [24]

Answer:With gravity, two things with mass will want to move toward each other. However, we humans don't feel our gravity pulling on another person because it's not very big, but we do all feel the pull of Earth's gravity all the time - we're not all floating in the air, because that would be happening without Earth's gravity!

Explanation:

4 0
3 years ago
The work done by an external force to move a -6.70 μc charge from point a to point b is 1.20×10−3 j .
ASHA 777 [7]

Answer:

108.7 V

Explanation:

Two forces are acting on the particle:

- The external force, whose work is W=1.20 \cdot 10^{-3}J

- The force of the electric field, whose work is equal to the change in electric potential energy of the charge: W_e=q\Delta V

where

q is the charge

\Delta V is the potential difference

The variation of kinetic energy of the charge is equal to the sum of the work done by the two forces:

K_f - K_i = W + W_e = W+q\Delta V

and since the charge starts from rest, K_i = 0, so the formula becomes

K_f = W+q\Delta V

In this problem, we have

W=1.20 \cdot 10^{-3}J is the work done by the external force

q=-6.70 \mu C=-6.7\cdot 10^{-6}C is the charge

K_f = 4.72\cdot 10^{-4}J is the final kinetic energy

Solving the formula for \Delta V, we find

\Delta V=\frac{K_f-W}{q}=\frac{4.72\cdot 10^{-4}J-1.2\cdot 10^{-3} J}{-6.7\cdot 10^{-6}C}=108.7 V

4 0
3 years ago
Read 2 more answers
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