The final speed of the orange is 7.35 m/s
Explanation:
The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration
towards the ground. So we can use the following suvat equation:

where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time elapsed
For the orange in this problem, we have
u = 0 (it is dropped from rest)
is the acceleration
Substituting t = 0.75 s, we find the final velocity (and speed) of the orange:

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Answer:
A. 3,000,000 m
B. 0.25 km
C. 10 m
D. 1,000 cm
Explanation:
no hablo español, así que solo ingrese esto en el traductor de G*ogle
A. One kilometer equals 1000 meters, so
3,000*1,000 = 3,000,000 m
B. One meter equals 0.001 kilometer, so
250*0.001 = 0.25 km
C. One centimeter equals 0.01 meter
1,000*0.01 = 10 m
D. One milimeter equals 0.1 centimer, so
10,000*0.1 = 1,000
When people aboard a plane...the amount of baggage you take has to vary because the plane has a certain carrying capacity.
D. Speed and direction, this is because velocity is a vector quantity so has a magnitude and direction assigned to it because it is the rate of change of displacement.