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4 years ago

Which part of an atom is actively exchanged or shared in a chemical bond?

Physics

2 answers:

RideAnS [48]4 years ago

6 0

<em>The part of an atom that is actively exchanged or shared in a chemical bond is the;</em>

B. Electron

<u>Electrons are negatively charged atoms.The electron is actively exchanged in a chemical bond </u>

Naddika [18.5K]4 years ago

3 0

Which part of an atom is actively exchanged or shared in a chemical b or shared in a chemical bond

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2 years ago

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A woman is 1.6 m tall and has a mass of 50 kg. She moves past an observer with the direction of the motion parallel to her heigh

eduard

To solve this problem it is necessary to apply the concepts related to linear momentum, velocity and relative distance.

By definition we know that the relative velocity of an object with reference to the Light, is defined by

$V_0 = \frac{V}{\sqrt{1-\frac{V^2}{c^2}}}$

Where,

V = Speed from relative point

c = Speed of light

On the other hand we have that the linear momentum is defined as

P = mv

Replacing the relative velocity equation here we have to

$P = \frac{mV}{\sqrt{1-\frac{V^2}{c^2}}}$

$P^2 = \frac{m^2V^2}{1-\frac{V^2}{c^2}}$

$P^2 = \frac{P^2V^2}{c^2}+m^2V^2$

$P^2 = V^2 (\frac{P^2}{c^2}+m^2)$

$V^2 = \frac{P^2}{\frac{P^2}{c^2}+m^2}$

$V^2 = \frac{(2.1*10^10)^2}{\frac{(2.1*10^10)^2}{(3.8*10^8)^2}+50^2}$

$V = 2.81784*10^8m/s$

Therefore the height with respect the observer is

$l = l_0*\sqrt{1-\frac{V^2}{c^2}}$

$l = 1.6*\sqrt{1-\frac{(2.81*10^8)^2}{(3*10^8)^2}}$

$l = 0.56m$

Therefore the height which the observerd measure for her is 0.56m

8 0

3 years ago

Someone please help!!

mart [117]

The answer is a.
The graph's line is higher if velocity is higher, and lower if velocity is lower. This is because the y axis is velocity. Thus, the fastest (highest velocity) that the car went is when the line was highest, and that is when x is 1.

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4 years ago