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fiasKO [112]
4 years ago
11

Which part of an atom is actively exchanged or shared in a chemical bond?

Physics
2 answers:
RideAnS [48]4 years ago
6 0

<em>The part of an atom that is actively exchanged or shared in a chemical bond is the;</em>

B. Electron

<u>Electrons are negatively charged atoms.The electron is actively exchanged in a chemical bond </u>

Naddika [18.5K]4 years ago
3 0
Which part of an atom is actively exchanged or shared in a chemical b or shared in a chemical bond
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Due today HELP HELP HELP
Anna [14]

Vas happenin!

Independent variable : amount of water each day

Dependent variable: water on the windsill

Hypotheses: Ben wants to try by adding water each day to two different places. Will that work? Will that effect the water?


Hope this helps you out

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-Zayn Malik
5 0
3 years ago
If it takes 20n to move a box, how much power will be needed to move the box a diatance
solmaris [256]

The power applied to move the box anywhere is

   (20 n) x (distance moved) / (time to move the distance) .
 
3 0
3 years ago
How does the sun's heat affect the humidity of a place​
Sunny_sXe [5.5K]

Answer:

the sun's heat affects humidity of how warm the air feels to us.

i tried

5 0
3 years ago
A particle (m = 4.3 × 10^-28 kg) starting from rest, experiences an acceleration of 2.4 × 10^7 m/s^2 for 5.0 s. What is its de B
Novay_Z [31]

Answer:

Wavelength, \lambda=1.28\times 10^{-14}\ m

Explanation:

Given that,

Mass of the particle, m=4.3\times 10^{-28}\ kg

Acceleration of the particle, a=2.4\times 10^7\ m/s^2

Time, t = 5 s

It starts from rest, u = 0

The De Broglie wavelength is given by :

\lambda=\dfrac{h}{mv}

v = a × t

\lambda=\dfrac{h}{mat}

\lambda=\dfrac{6.67\times 10^{-34}}{4.3\times 10^{-28}\times 2.4\times 10^7\times 5}

\lambda=1.28\times 10^{-14}\ m

Hence, this is the required solution.

4 0
3 years ago
James accelerates his skate board uniformly along a straight road from rest to 10 m/s in 4 seconds. What is James Acceleration?
lawyer [7]

Given:

u(initial velocity)=0

v(final velocity)= 10 m/s

t= 4 sec

Now we know that

v= u + at

Where v is the final velocity

u is the initial velocity

a is the acceleration measured in m/s^2

t is the time measured in sec

10=0+ax4

a=10/4

a=2.5 m/s^2

4 0
3 years ago
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