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fiasKO [112]
4 years ago
11

Which part of an atom is actively exchanged or shared in a chemical bond?

Physics
2 answers:
RideAnS [48]4 years ago
6 0

<em>The part of an atom that is actively exchanged or shared in a chemical bond is the;</em>

B. Electron

<u>Electrons are negatively charged atoms.The electron is actively exchanged in a chemical bond </u>

Naddika [18.5K]4 years ago
3 0
Which part of an atom is actively exchanged or shared in a chemical b or shared in a chemical bond
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3 years ago
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A cylindrical metal specimen having an original diameter of 11.77 mm and gauge length of 46.1 mm is pulled in tension until frac
Marta_Voda [28]

Answer:

% reduction in area = 54.26 %

percentage elongation = 43.16 %

Explanation:

a) percentage reduction in area = \frac{(A_1 - A_2)}{A_1 } * 100

A_1  =\pi r^2 = \pi * 5.88^2=108.8 mm2

A_2=\pi * 3.98^2= 49.97 mm2

% reduction in area =\frac{(108.8 - 49.97)}{108.8} * 100 = 54.26 %

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5 0
3 years ago
A 66​-foot-tall woman walks at 55 ​ft/s toward a street light that is 2424 ft above the ground. What is the rate of change of th
I am Lyosha [343]

Answer:

a. \frac{dx}{dt}=20ft/s

b. \frac{d(x+L)}{dt}==25ft/s

Explanation:

Using the triangle theorem both triangle the woman makes between the light so the rate of change of length can use geometry first

tan(\beta)=\frac{24ft}{L+x}=\frac{6ft}{x}

Solve to find the rate relation

x=\frac{24}{6}*L

x=4*L

Now the rate of the change rate

\frac{dx}{dt}=4*\frac{dL}{dt}

\frac{dx}{dt}=4*5ft/s=20ft/s

Finally the rate of her shadow moving

\frac{d(x+L)}{dt}=\frac{dx}{dt}+\frac{dL}{dt}

\frac{d(x+L)}{dt}=20ft/s+5ft/s=25ft/s

5 0
3 years ago
a sound pulse emitted underwater reflects off a school of fish and is detected at the same place 0.01 s later. how far away are
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In fresh water sound waves travel at 1497m/s at 25 degrees, I'll assume that's the characteristics of the water.

If it's 0.01s then you need to divide the speed by 100 to get the, 14.97, however it gets there and back in that time so you need to halve it.
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3 years ago
How much total work is done by the force in lifting the elevator from 0.0 m to 9.0 m?
aksik [14]
The total work is

         (mass of the elevator, kg) x (9.8 m/s²) x (9.0 m)           Joules .
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3 years ago
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