Question

Find the intensity of a 55 dB sound given I 0=10^-12W/m^2

Answer 1

Answer:

3.16 × $10^{-7}$ W/$m^{2}$

Explanation:

β(dB)=10 × $log_{10}(\frac{I}{I_{0} })$

$I_{0}$=$10^{-12}$ W/$m^{2}$

β=55 dB

Therefore plugging into the equation the values,

55=10 $log_{10}(\frac{I}{ [tex]10^{-12}$})[/tex]

5.5= $log_{10}(\frac{I}{ [tex]10^{-12}$})[/tex]

$10^{5.5}$= $\frac{I}{10^{-12} }$

316227.76×$10^{-12}$= I

I= 3.16 × $10^{-7}$ W/$m^{2}$