Answer:
m∠1 = 50°, m∠2 = 90°, m∠3 = 40°, and m∠4 = 50°
Step-by-step explanation:
Angles on straight line are equal;
Vertical angles are equal,
Complementary angles add up to 90°.
Angles on straight line adds up to 180°
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Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan= 5/11.65
=23.23°
AC= km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
