Answer:

Explanation:
<u>Instant Acceleration</u>
The kinetic magnitudes are usually related as scalar or vector equations. By doing so, we are assuming the acceleration is constant over time. But when the acceleration is variable, the relations are in the form of calculus equations, specifically using derivatives and/or integrals.
Let f(t) be the distance traveled by an object as a function of the time t. The instant speed v(t) is defined as:

And the acceleration is

Or equivalently

The given height of a projectile is

Let's compute the speed

And the acceleration

It's a constant value regardless of the time t, thus

<span>(20 cm)/(5 sec) = (0.20 meters)/(5 seconds)
</span>
Answer:
The resistance that will provide this potential drop is 388.89 ohms.
Explanation:
Given;
Voltage source, E = 12 V
Voltage rating of the lamp, V = 5 V
Current through the lamp, I = 18 mA
Extra voltage or potential drop, IR = E- V
IR = 12 V - 5 V = 7 V
The resistance that will provide this potential drop (7 V) is calculated as follows:
IR = V

Therefore, the resistance that will provide this potential drop is 388.89 ohms.
Answer:
a

b

Explanation:
From the question we are told that
The diameter of the Ferris wheel is 
The period of the Ferris wheel is 
The mass of the passenger is 
The apparent weight of the passenger at the lowest point is mathematically represented as

Where
is the centripetal force on the passenger, which is mathematically represented as

Where
is the angular velocity which is mathematically represented as

substituting values


and r is the radius which is evaluated as 
substituting values


So


W is the weight which is mathematically represented as


So


The apparent weight of the passenger at the highest point is mathematically represented as

substituting values


Answer:
<h3>The answer is 50 N</h3>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
<h3>force = mass × acceleration</h3>
From the question we have
force = 10 × 5
We have the final answer as
<h3>50 N</h3>
Hope this helps you