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nevsk [136]
3 years ago
8

Which phrase best describes wave motion?

Physics
1 answer:
Fittoniya [83]3 years ago
6 0
I think the correct answer from the choices listed above is option A. Wave motion is a  movement of energy through space or a medium . Some waves are visible light waves, heat waves, sound waves and the like. Hope this answers the question.
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NEED HELP Two skaters stand facing each other. One skater’s mass is 60 kg, and the other’s mass is 72 kg. If the skaters push aw
stealth61 [152]

Answer:

the heavier skater has less momentum

hope it is helpful to you

3 0
2 years ago
Read 2 more answers
Two children who are bored while waiting for their flight at the airport decide to race from one end of the 20-m-long moving sid
QveST [7]

Answer: Phillipe wins the race

Explanation:

Given

Length of track=20 m

Velocity of Phillippe=2 m/s w.r.t sidewalk

Velocity of sidewalk=1.5 m/s

Rena velocity=2 m/s

Therefore absolute velocity of P is 2+1.5=3.5 m/s

Time taken by phillippe \frac{20}{3.5}+\frac{20}{3.5-1.5}

t_P=5.714+10=15.714 s

Time taken by rena

t_r=\frac{20}{2}+\frac{20}{2}=20 s

as the time taken  by phillippe is less than rena therefore Phillippe wins the race.

8 0
3 years ago
Read 2 more answers
h(t) = - 16t2 + 64t + 112 where t is the time in seconds. After how many seconds does the arrow reach it maximum height? Round t
laila [671]

Answer:

2 seconds

Explanation:

The function of height is given in form of time. For maximum height, we need to use the concept of maxima and minima of differentiation.

h(t)=-16t^{2}+64t+112

Differentiate with respect to t on both the sides, we get

\frac{dh}{dt}=-32t+64

For maxima and minima, put the value of dh / dt is equal to zero. we get

- 32 t + 64 = 0

t = 2 second

Thus, the arrow reaches at maximum height after 2 seconds.

8 0
3 years ago
1. An object is projected upward with a velocity of 125 m/s.
grigory [225]

Answer:

A) s = 796.38 m

B) t = 12.742 s

C) T = 25.484 s

Explanation:

A) First of all let's find the time it takes to get to maximum height using Newton's first equation of motion.

v = u + gt

u = 125 m/s

v = 0 m/s

g = 9.81 m/s²

Thus;

0 = 125 - 9.81(t)

g is negative because motion is against gravity. Thus;

9.81t = 125

t = 125/9.81

t = 12.742 s

Max height will be gotten from Newton's 2nd equation of motion;

s = ut + ½gt²

s = (125 × 12.742) + (½ × -9.81 × 12.742²)

s = 1592.75 - 796.37

s = 796.38 m

B) time to reach maximum height is;

t = u/g

t = 125/9.81

t = 12.742 s

C) Total time elapsed is;

T = 2u/g

T = 2 × 125/9.81

T = 25.484 s

4 0
3 years ago
How to solve this step by step
-BARSIC- [3]
I think one hour, sorry if i'm wrong 
8 0
3 years ago
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