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Drupady [299]
3 years ago
13

What is the power p supplied to a resistor whose resistance is r when it is known that it has a voltage δv across it?

Physics
1 answer:
enyata [817]3 years ago
4 0
... power p supplied to a resistor whose resistance is r when it is known that it has a voltage δv across ... supplied to a resistor whose resistance
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An elevator manufacturing company is stress-testing a new elevator in an airless test shaft. The elevator is traveling at an unk
devlian [24]

Answer:

3.192 m/s

Explanation:

t = Time taken = 0.900 seconds

u = Initial velocity

v = Final velocity

s = Displacement = 1.1 meters

a = Acceleration due to gravity = 9.81 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow u=\frac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\frac{1.1-\frac{1}{2}\times 9.81\times 0.9^2}{0.9}\\\Rightarrow u=-3.192\ m/s

Velocity of the elevator when it snapped is 3.192 m/s

4 0
3 years ago
Which of the following forces best represents an equilibrant force in this system?
irina [24]
The answer is:  (2) :  <span>↘ 
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4 0
3 years ago
Which word is not a good way to describe exercise?
Karolina [17]
In my opinion, calling exercise "work"  wouldn't be a good way of describing it, I don't think people would exercise if its called work 
3 0
3 years ago
Imagine you are on the top of a mountain with four basketballs. The mass of the four basketballs are 100 kilograms, 200 kilogram
pentagon [3]

Answer:

400 kilogram

Explanation:

Force exerted is directly proportional to the mass of an object.

F=ma where m is mass and a is acceleration. Taking uniform acceleration on all objects then the larger the mass the higher the force and vice versa. Theredore, among the masses given, 400 kilograms is the largest hence it exerts the largest force at the bottom

5 0
3 years ago
Can someone please help me ASAP
Serggg [28]

Answer:

distance = 6.1022 x10^16[m]

Explanation:

To solve this problem we must use the formula of the average speed which relates distance to time, so we have

v = distance / time

where:

v = velocity = 3 x 10^8 [m/s]

distance = x [meters]

time = 6.45 [light years]

Now we have to convert from light-years to seconds in order to get the distance in meters.

t = 6.45 [light-years]*365[\frac{days}{1light-year}]*24[\frac{hr}{1day}] *60[\frac{min}{1hr}]*60[\frac{seg}{1min} ] =203407200 [s]

Now using the formula:

distance = v * time

distance = (3*10^8)*203407200

distance = 6.1022 x10^16[m]

8 0
3 years ago
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