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yKpoI14uk [10]
3 years ago
7

Based on the time measurements in the table, what can

Physics
2 answers:
nignag [31]3 years ago
6 0

Answer:

1. The car can go faster on a higher track

2. short

3.0.56 M/S

Explanation:

Technically this ones easy if you read the questions thats how i got mine

Vera_Pavlovna [14]3 years ago
5 0

Answer:

1) car travel faster on the higher track

2) shorter

3) 0.56m/s

Explanation:

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4 years ago
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Inert gas used to make bright city lights True or False
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3 years ago
A tennis ball is thrown from a 25 m tall building with a zero initial velocity. At the same moment, another ball is thrown from
Nataly [62]

Answer:

The two balls meet in 1.47 sec.

Explanation:

Given that,

Height = 25 m

Initial velocity of ball= 0

Initial velocity of another ball = 17 m/s

We need to calculate the ball

Using equation of motion

s=ut+\dfrac{1}{2}gt^2+h

Where, u = initial velocity

h = height

g = acceleration due to gravity

Put the value in the equation

For first ball

s_{1}=0-\dfrac{1}{2}gt^2+25....(I)

For second ball

s_{2}=17t-\dfrac{1}{2}gt^2+0....(II)

From equation (I) and (II)

-\dfrac{1}{2}gt^2+25=17t-\dfrac{1}{2}gt^2+0

t=\dfrac{25}{17}

t=1.47\ sec

Hence, The two balls meet in 1.47 sec.

6 0
4 years ago
Which of the following is the reason a wedge is used in a knife? A)increases the effort force B)decreases the effort force C)cha
Tatiana [17]
The answer is d decreases the resistance force
8 0
3 years ago
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4. With respect to a mass of 1kg. (a) How much change in elevation must it undergo to change its potential energy by 1 kJ? (g=9.
mojhsa [17]

Answer:

102 m upwards.

Explanation:

Just from a qualitative analysis we can tell the mass it needs to go upwards. How much we determine with the fact that the increase will be - in absolute value - equal to the work gravity does on it to go down that same distance.

Fixed that work being 1 kJ, we get

\vec F \cdot \vec{ \Delta h} = |F| |\Delta h| cos 0 = ( 9.8 N )\Delta h \cdot 1 = 10^3 J\\\Delta h = \frac {10^3}{9,8} m \approx 102 m

4 0
2 years ago
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