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3 years ago

magnitude of velocity does not change but the direction changes. Can we say that it is an accelerated motion?

Physics

1 answer:

Olenka [21]3 years ago

4 0

Answer:

MRCORRECT has answered the question

Explanation:

Since velocity is a vector, it can change either in magnitude or in direction. Acceleration is therefore a change in either speed ordirection, or both. Keep in mind that althoughacceleration is in the direction of the changein velocity, it is not always in the direction ofmotion.

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Refraction occurs when a wave changes its A) color. B) frequency. C) intensity. D) speed.

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Two containers (A and B) are in thermal contact with an environment at temperature T = 280 K. The two containers are connected b

zmey [24]

Answer:

The maximum amount of work is $W = 1563.289 \ J$

Explanation:

From the question we are told that

The temperature of the environment is $T = 280\ K$

The volume of container A is $V_A = 2 m^3$

Initially the number of moles is $n = 1.2 \ moles$

The volume of container B is $V_B = 3.5 \ m^3$

At equilibrium of the gas the maximum work that can be done on the turbine is mathematically represented as

$W = P_A V_A ln[ \frac{V_B}{V_A} ]$

Now from the Ideal gas law

$P_A V_A = nRT$

So substituting for $P_A V_A$ in the equation above

$W = nRT ln [\frac{V_B}{V_A} ]$

Where R is the gas constant with a values of $R = 8.314 \ J/mol$

Substituting values we have that

$W = 1.2 * (8.314) * (280) * ln [\frac{3.5}{2} ]$

$W = 1563.289 \ J$

8 0

3 years ago

If it takes 50.0 seconds to lift 10.0 Newtons of books to a height of 7.0

Ilya [14]

Work of the force = 10 N

Time required for the work = 50 sec

Height = 7 m

We are given with the value of work and time in the question.

Substitute the values in the formula of power and then you'll get the power required.

We know that,

w = Work

p = Power

t = Time

By the formula,

Given that,
Work (w) = 7 m = 70 Joules
Time (t) = 50 sec
Substituting their values,

p = 70/50

p = 1.4 watts

Therefore, the power required is 1.4 watts.

Hope it helps!

3 0

3 years ago