The unbalanced Equation is
electricity
KI (aq) + H2O (l) -------------> H2 (g) + I2(g) + KOH(aq)
Answer:
3.25 M
Explanation:
Number of moles = mass/ molar mass
mass of NaOH = 65 g
Molar mass of NaOH = 40 g/mol
Number of moles of NaOH = 65g/40 g/mol = 1.625 moles
Let us recall that;
n = CV
n = number of moles of solute
C = concentration of solution
V = volume of solution
C = n/V
n = 1.625 moles
V = 500/1000 L = 0.5 L
C = 1.625 moles/0.5
C = 3.25 M
Answer:
The answer is the explanation.
Explanation:
The acetic acid, CH3COOH, reacts with calcium hydroxide, Ca(OH)2, producing acetate ion, CH3COO- and water as follows:
2CH3COOH + Ca(OH)2 → 2CH3COO- + 2H2O + Ca²⁺
That means the moles of acetic acid decrease whereas the moles of acetate ion are increased. The ratio of [CH3COOH] / [CH3COO-] is different.
As a base is added, the concentration of H3O+ decreases increasing the pH.
That means:
<em>TRUE </em> A. The number of moles of CH3COOH will decrease.
<em>FALSE</em> B. The number of moles of CH3COO- will decrease.
<em>TRUE </em>C. The equilibrium concentration of H3O will decrease.
<em>FALSE </em>D. The pH will decrease.
<em>FALSE</em> E. The ratio of [CH3COOH] / [CH3COO-] will remain the same.
Answer:
A) oxidizing agent is SO2
B) NaClO is the oxidizing agent
Explanation:
A) This is a redox reaction in which oxidation and reduction occur simultaneously.
Thus, in 2H2S(g) + SO2(g) -> 2H2O(l) + 3S(s);
H2S is reduced as follows;
H2S → S + 2H+ + 2e−
We can see that SO2 has been reduced while H2S gets oxidized since it has changed state from - 2 to 0 . Thus sulphur dioxide is the oxidizing agent.
B) SO2(g) + H2O(l) + NaClO(aq) -> NaCl(aq) + H2SO4(aq)
In this, SO2 undergoes oxidation and NaClO is the oxidizing agent
This is the answer hope it helps you!!
