It's kinda long but...
A tectonic setting where volcanic action occurs is called <span>a </span>hot-spot (intraplate<span>), which describes volcanic activity that occurs </span>within tectonic plates<span> and is generally NOT related to plate boundaries and plate movements.
</span>Hope this helps!!:)
Answer:
Explanation:
Knowing that the formula for average velocity is:
Being said that, we know that the person's displacement is zero because it returns to its starting point
That means 
Explanation:
In a vacuum (no air resistance), it doesn't. All falling objects, regardless of mass, accelerate at the same rate.
However, when air resistance is taken into account, heavier objects indeed fall faster than lighter objects, provided they have the same shape and size. For example, a lead ball falls faster than a styrofoam ball.
To understand why, first look at what factors affect air resistance:
D = ½ρv²CA
where ρ is air density,
v is velocity,
C is drag coefficient,
and A is cross sectional area.
As falling objects accelerate, they eventually reach a maximum velocity where air resistance equals weight. This is called terminal velocity.
D = W
½ρv²CA = mg
v = √(2mg/(ρCA))
If we increase m while holding everything else constant, v increases. So two objects with the same size and shape but different masses will have different terminal velocities, with the heavier object falling faster.
Answer:
5.38 m/s
Explanation:
Given (in the x direction):
Δx = 2.45 m
v₀ = v cos 42.5°
a = 0 m/s²
Δx = v₀ t + ½ at²
(2.45 m) = (v cos 42.5°) t + ½ (0 m/s²) t²
2.45 = (v cos 42.5°) t
t = 3.32 / v
Given (in the y direction):
Δy = 0.373 m
v₀ = v sin 42.5°
a = -9.8 m/s²
Δx = v₀ t + ½ at²
(0.373 m) = (v sin 42.5°) t + ½ (-9.81 m/s²) t²
0.373 = (v sin 42.5°) t − 4.905 t²
0.373 = (v sin 42.5°) (3.32 / v) − 4.905 (3.32 / v)²
0.373 = 2.25 − 54.2 / v²
v = 5.38
Graph:
desmos.com/calculator/5n30oxqmuu
The acceleration is 2.2 m/s^2 and the net force is 62N towards the right
<h3>What is the net force?</h3>
The net force is the effective force that acts on a body in a give direction.
1. The net force in the y axis is; ∑Fy = 0
2. The net force along the y axis is; ∑Fx = 277 N - 215 N
3. The normal reaction is given by; 28 kg * 9.8 m/s^2 = 274.4 N
4. The net force in the x axis is 277 N - 215 N = 62N towards the right
5. The acceleration of this force is obtained from;
F = ma
62 = 28 a
a = 62/28
a = 2.2 m/s^2
Learn more about the net force:brainly.com/question/18031889
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