Answer:
A.) (7t³ + 2k^4)(7t³ - 2k^4)
Step-by-step explanation:
Factor the following:
49 t^6 - 4 k^8
49 t^6 - 4 k^8 = (7 t^3)^2 - (2 k^4)^2:
(7 t^3)^2 - (2 k^4)^2
Factor the difference of two squares. (7 t^3)^2 - (2 k^4)^2 = (7 t^3 - 2 k^4) (7 t^3 + 2 k^4):
Answer: (7 t^3 - 2 k^4) (7 t^3 + 2 k^4)
Answer:
Multiply dno. plus nume. by 2
Step-by-step explanation:
get a base of 100
There are 12 inches in a foot, so 9ft = 108in. Also, 80% = 0.8. Therefore the formula is:
h(n) = 108 * 0.8^n.
To find the bounce height after 10 bounces, substitute n=10 into the equation:
h(n) = 108 * 0.8^10 = 11.60in (2.d.p.).
Finally to find how many bounces happen before the height is less than one inch, substitute h(n) = 1, then rearrage with logarithms to solve for the power, x:
108 * 0.8^x = 1;
0.8^x = 1/108;
Ln(0.8^x) = ln(1/108);
xln(0.8) = ln(1\108);
x = ln(1/108) / ln(0.8) = -4.682 / -0.223 = 21 bounces
-4 + -7= -11
When adding negative numbers if the are both negative then you add them. When you have a negative and a positive you subtract. In this problem they just took out the plus sign.
Answer:
65 feet below sea level.
Step-by-step explanation:
With the information provided, we can create the following equation for the position of the sea lion (p)
p = 3x - 10
In this equation, x would be the final position of the seal when it caught the fish. Since we are told that the seal's position is 25 feet below sea level then we can plug in this value as x and solve for p...
p = (3 * 25) - 10
p = 75 - 10
p = 65
Finally, we can see that the sea lion's position is 65 feet below sea level.
